Question

我正在尝试创建一个将在启动时启动的服务。

我在adb中看到以下错误：

05-31 10:14:24.060 E/AndroidRuntime( 1583):java.lang.RuntimeException: Unable to instantiate receiver MyNameSpace.MyClass.MyBootReceiver: java.lang.ClassNotFoundException: Didn't find class "MyNameSpace.MyClass.MyBootReceiver" on path: /data/app/MyNameSpace.MyClass-1.apk
05-31 10:14:24.060 E/AndroidRuntime( 1583): Caused by: java.lang.ClassNotFoundException: Didn't find class "MyNameSpace.MyClass.MyBootReceiver" on path: /data/app/MyNameSpace.MyClass-1.apk

问题是，我肯定看到MyBootReceiver类存在于MyNameSpace中，作为MyClass的子类，所以它看起来像< em>应能够找到它。

我的清单定义为：

<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android" 
          android:versionCode="1" 
          android:versionName="1.0" 
          package="MyNamespace.MyClass">
    <uses-sdk />
    <uses-permission android:name="android.permission.INTERNET" />
    <uses-permission android:name="android.permission.RECEIVE_BOOT_COMPLETED"/>

  <application>
    <receiver android:name=".MyBootReceiver">
      <intent-filter>
        <action android:name="android.intent.action.BOOT_COMPLETED" />
      </intent-filter>
    </receiver>
    <activity android:name=".MyActivity"></activity>

  </application>    
</manifest>

，这是代码：

namespace MyNamespace
{
    [Service]
    [IntentFilter(new String[] { "com.xamarin.MyClass" })]
    public class MyClass : IntentService
    {
        private IBinder binder;

        public const string MyUpdatedAction = "MyUpdated";

        protected override void OnHandleIntent(Intent intent)
        {
            var myIntent = new Intent(MyUpdatedAction);

            SendOrderedBroadcast(myIntent, null);
        }

        public override IBinder OnBind(Intent intent)
        {
            binder = new MyServiceBinder(this);
            return binder;
        }

        [BroadcastReceiver]
        [IntentFilter(new string[] { MyUpdatedAction }, Priority = (int)IntentFilterPriority.LowPriority)]
        public class MyBootReceiver : BroadcastReceiver
        {
            public override void OnReceive(Context context, Android.Content.Intent intent)
            {
                Log.Info("MyTrace", "MyReceiver OnReceive action: " + intent.Action);

                if (intent.Action.Contains("BOOT_COMPLETED"))
                {
                    var pushIntent = new Intent(MyUpdatedAction);
                    context.StartService(pushIntent);

                }
            }
        }
    }
}

我需要做些什么来使这件事有效？

Answer 1

我通常在描述清单文件中的项目时添加整个类路径。所以在你的情况下我会写：

<application>
    <receiver android:name="MyNamespace.MyBootReceiver">
      <intent-filter>
        <action android:name="android.intent.action.BOOT_COMPLETED" />
      </intent-filter>
    </receiver>
<activity android:name="MyNamespace.MyActivity"></activity>

这可能与Why is this simple service not starting?相同。

Answer 2

我遇到了同样的问题并找到了解决方案。按照以下步骤使“内部”BroadcastReceiver正常运行，不会发生任何崩溃：

1）让你的mainActivity看起来像这样：

public class MainActivity extends AppCompatActivity
    implements SomeListener {
        MyReceiver myRecvr;
        @Override
        protected void onCreate(Bundle savedInstanceState) {
           super.onCreate(savedInstanceState);
           myRecvr = new MyReceiver();  
           .......
        }

    ...onResume() code ... onPause() code ... yourBroadcastReceiver Class{} ...


}

2）在onResume（）中注册接收器并在onPause（）中取消注册接收器，如下所示：

@Override
public void onResume() {
    Log.e("DEBUG", "onResume()");
    final IntentFilter filter = new IntentFilter();
    filter.addAction("MyBroadcast");

    registerReceiver(myRecvr, filter);
    super.onResume();
}

@Override
public void onPause() {
    Log.e("DEBUG", "OnPause()");
    unregisterReceiver(myRecvr);
    super.onPause();
}

3）现在在onPause（）下面或者在mainActivity类结束之前添加你的内部BroadcastReceiver：

public static class MyReceiver extends BroadcastReceiver {

    @Override
    public void onReceive(Context context, Intent intent) {
        Bundle extras = intent.getExtras();
        if (extras != null) {
            if(extras.containsKey("value")){
                Log.e("BroadcastedValue",extras.get("value").toString());
            }
        }
    }
}

4）最后，确保已将内部BroadcastReceiver路径添加到清单中，如下所示：

<receiver android:name="com.example.yourproject.YourMainActivityName$MyReceiver" android:enabled="true">
        <intent-filter>
            <action android:name="MyBroadcast" >
            </action>
        </intent-filter>
    </receiver>

Android无法找到我的BroadcastReceiver。我究竟做错了什么？

2 个答案: