Question

假设我没有名为Animals的用户友好表。像这样：

ID NAME CHANGED
1  Dog  2016-01-02
2  Dog  2016-01-05
3  Dog2 2016-01-05
4  Dog3 2016-01-06
5  Cat  2016-01-06
6  Fish 2016-01-07
7  Cat2 2016-01-07

我想知道表中有多少相似的单词以相同的方式开始，但可能会以不同的方式结束。此外，我只想显示没有额外'2'或'3'的姓名。更确切地说，我想要这样的结果：

Counted NAME
4       Dog
2       Cat
1       Fish

以下是我一直试图与之相处的代码（尝试了很多方法）：

SELECT COUNT(
CASE
    WHEN NAME LIKE '%' + NAME + '%' THEN 1
        ELSE 0
END
) AS Counted, NAME FROM Animals
WHERE NAME LIKE '%' + NAME + '%' AND
    NAME NOT LIKE '%2' AND
    NAME NOT LIKE '%3'
    GROUP BY NAME
    ORDER BY Counted DESC

Answer 1

繁琐但简单的方法是从数字字符中删除数据：

select new_name,
       count(*) as counted
from   (
       select replace(replace(replace....replace(Name, '0', ''), '1', ''), '2','')... as new_name
       from   Animals
       ) as a
group by new_name

Answer 2

select case when patIndex('%[0-9]', val) = 0 then val  
    else substring(val, 1, patIndex('%[0-9]', val)-1) end,  count(*)
from table
Group by case when patIndex('%[0-9]', val) = 0 then val  
    else substring(val, 1, patIndex('%[0-9]', val)-1) end

Answer 3

你必须在单独的表中定义动物类别，这将永远无法解决。对于同一动物的拼写不同，分组将非常困难。

如果它始终是动物名称末尾的数字，那么

select left(Name,isnull(nullif(patindex('%[0-9]%',Name)-1,-1),len(Name))),count(1)
From yourtable 
Group by left(Name,isnull(nullif(patindex('%[0-9]%',Name)-1,-1),len(Name)))

Answer 4

这将删除数据中的所有数字，无论数据中有多少数字或数据存在于何处。这有点荒谬，但有时SQL只是......

declare @t table(ID int, Name nvarchar(10), Changed date);
insert into @t values
 (1  ,'Dog','20160102')
,(2  ,'Dog','20160105')
,(3  ,'Dog2','20160105')
,(4  ,'Dog30','20160106')
,(5  ,'Cat','20160106')
,(6  ,'Fish','20160107')
,(7  ,'Cat27676','20160107');

select count(1) as Counted
        ,replace(replace(replace(replace(replace(replace(replace(replace(replace(replace(Name
            , '0', ''),'1', ''),'2', ''),'3', ''),'4', ''),'5', ''),'6', ''),'7', ''),'8', ''),'9', '') as Name
from @t
group by replace(replace(replace(replace(replace(replace(replace(replace(replace(replace(Name
            , '0', ''),'1', ''),'2', ''),'3', ''),'4', ''),'5', ''),'6', ''),'7', ''),'8', ''),'9', '')
order by Counted desc;

输出：

+---------+------+
| Counted | Name |
+---------+------+
|       4 | Dog  |
|       2 | Cat  |
|       1 | Fish |
+---------+------+

SQL Count类似记录

4 个答案: