Question

嗯，我之前发布了一个类似的问题，并得到了一个解决方案，但我正在做类似的事情和一点点不同，我需要一些帮助。

有一个搜索者表，雇主表，类别表，兴趣表......

FK_is_id = Seeker ID
FK_ie_id = Employer ID
FK_ic_id = Category ID

兴趣表数据：

int_id   FK_is_ID  FK_ie_ID  FK_ic_ID
1           2          null      3
2           2          null      5
3           null       1         3
4           null       3         1
5           null       2         5
6           4          null      1

我想要做的是，过滤掉与雇主（eid）有相同兴趣的雇主（FK_ie_ID），像竞争对手或竞争对手。

使用以下查询，我能够做我想要的，问题是，它还在结果中重新登录用户....我只是登录用户以外的雇主..

SELECT ins.int_id, ins.FK_is_ID, ine.FK_ie_ID,ins.FK_ie_ID,emp.e_name,ine.int_id
FROM Interests ins
INNER JOIN Interests ine ON ins.FK_ic_ID = ine.FK_ic_ID
FULL OUTER JOIN employers emp ON emp.e_id=ine.FK_ie_id
WHERE ins.FK_ie_ID = @eid
  AND ine.FK_ie_ID IS NOT null

Answer 1

我认为以下内容可以完成您的结果，您可以验证：

＆＃13;

DECLARE @eid INT
SELECT @eid = 3

DECLARE @Interest TABLE 
(
	int_id INT NOT NULL,
	FK_is_ID INT NULL,
	FK_ie_ID INT NULL,
	FK_ic_ID INT NULL
)

DECLARE @Employers TABLE 
(
	e_id INT NOT NULL,
	e_name VARCHAR(MAX) NULL
)

INSERT INTO @Interest
SELECT * FROM
(
	SELECT 1 AS int_id, 2		AS FK_is_ID, NULL	AS FK_ie_ID, 3 AS FK_ic_ID
	UNION ALL
	SELECT 2 AS int_id, 2		AS FK_is_ID, NULL	AS FK_ie_ID, 5 AS FK_ic_ID
	UNION ALL
	SELECT 3 AS int_id, NULL	AS FK_is_ID, 1		AS FK_ie_ID, 3 AS FK_ic_ID
	UNION ALL
	SELECT 4 AS int_id, NULL	AS FK_is_ID, 3		AS FK_ie_ID, 1 AS FK_ic_ID
	UNION ALL
	SELECT 5 AS int_id, NULL	AS FK_is_ID, 2		AS FK_ie_ID, 5 AS FK_ic_ID
	UNION ALL
	SELECT 6 AS int_id, 4		AS FK_is_ID, NULL	AS FK_ie_ID, 1 AS FK_ic_ID
) AS DATA

INSERT INTO @Employers
SELECT * FROM
(
	SELECT 1 AS e_id, 'one' AS e_name
	UNION ALL
	SELECT 2 AS e_id, 'two' AS e_name
	UNION ALL
	SELECT 3 AS e_id, 'three' AS e_name	
) AS DATA


SELECT 
	Interest.int_id, 
	Interest.FK_is_ID,
	Employers.e_name
FROM 
	@Interest AS Interest
LEFT OUTER JOIN
	@Employers AS Employers
	ON Interest.FK_ie_id = Employers.e_id	
INNER JOIN
	(
		SELECT
			InterestSub.FK_ic_ID
		FROM 
			@Interest AS InterestSub
		WHERE
			InterestSub.FK_ie_ID = @eid
	) AS SubData
	ON Interest.FK_ic_ID = SubData.FK_ic_ID
WHERE
	COALESCE(Interest.FK_ie_ID, '') <> @eid

＆＃13;

类似记录删除一个

1 个答案: