我有以下单身人士:
public abstract class Store<Input, Output> {
private BehaviorSubject<Input> subject = BehaviorSubject.create();
private Observable<Output> observable; //also a singleton
public final Subscription register(Subscriber<Output> subscriber) {
if (observable == null) {
observable = subject.compose(getTransformer()); //is this hot?
}
return observable.subscribe(subscriber);
}
public final void unregister(Subscription subscription) { //unregister }
//applies operators to the original stream to transform Input -> Output
protected abstract Observable.Transformer<Input, Output> getTransformer();
public final void onNext(Input event) { subject.onNext(event);}
}
问题:当我旋转设备或最小化应用程序时,可观察到的模具(中止网络执行)。 subject.compose()
是否会感冒可观察,如果是,为什么?。
我尝试使用publish.autoConnect()
/ share()
让它变热,现在它不会在轮换时死亡......但是BehaviourSubject
会中断。当我旋转设备时,我没有在订阅时获得第一个值。
如何转换subject
的输出值并使其表现为subject
? SAMPLE PROJECT
LOG:
USER:点击按钮从网络中获取
D:从中检索 网络... D:网络请求成功执行
D:缓存到记忆中 USER:点击按钮再次从网络获取
D:从网络中检索...
USER:按下主页按钮,应用程序背景
d:.unsubscribe()
答案 0 :(得分:0)
事实证明,我一直在使用主题错误。这是我想在上面实现的正确版本:
public abstract class RxStore<Input, Output> {
private BehaviorRelay<Output> relay;
public final Subscription register(Subscriber<Output> subscriber) {
if (relay == null) {
relay = BehaviorRelay.create(defaultValue());
}
return relay.subscribe(subscriber);
}
public final void unregister(Subscription subscription) {
if (subscription != null && !subscription.isUnsubscribed()) {
subscription.unsubscribe();
}
}
public void execute(Input event) {
buildObservable(event).subscribe(relay);
}
/**
* @return the first or default value emitted to subscribers
*/
protected Output defaultValue() {
return null;
}
/**
* @return an buildObservable responsible of handling its own errors.
*/
protected abstract Observable<Output> buildObservable(Input event);
}
编辑:
我发现这种方法非常有用。我正在使用这种方法,我写了一篇关于此的文章:
https://medium.com/@FerRaviola/rxandroid-an-event-bus-on-steroids-9699e93eca98#.tqbxleo4h