Question

def noalpha(s):

    noa = ''
    for c in s:
        if not (c in noa or c.isalpha()):
            noa += c
    return noa

def flines(t, ww):

    s=noalpha(t)
    lines=t.lower().splitlines()
    lst=[]
    for i in range(len(lines)):
        for caratteri in s:
            lines[i]=lines[i].replace(caratteri, ' ')
        wrdst=lines[i].split()
        l= 'Line ' +str(i)+': ' 
        False
        for k in ww:
            k=k.lower()
            num=wrdst.count(k)

            if num>0:
                l+='"'+ str(k) + '"=' + str(num)+' '
                True
        if True:
            lst+=[l]


    return lst

有人可以向我解释我如何修改输出以便不显示空行？运行程序后得到的输出是：

['Line 0: "to"=1 ', 'Line 1: "the"=1 ', 'Line 2: "the"=1 ', 'Line 3: "to"=1 ', 'Line 4: "so"=2 ', 'Line 5: ', 'Line 6: ', 'Line 7: "to"=1 "the"=1 ', 'Line 8: "to"=1 "the"=2 ', 'Line 9: ', 'Line 10: ', 'Line 11: "to"=1 "the"=1 ', 'Line 12: ', 'Line 13: ', 'Line 14: "so"=1 ', 'Line 15: "to"=1 ', 'Line 16: ', 'Line 17: ', 'Line 18: "to"=1 "the"=2 ', 'Line 19: "the"=1 ', 'Line 20: "the"=4 ', 'Line 21: ', 'Line 22: ', 'Line 23: ', 'Line 24: ', 'Line 25: ', 'Line 26: ', 'Line 27: "the"=1 ', 'Line 28: ', 'Line 29: ', 'Line 30: "the"=1 ', 'Line 31: ']

Answer 1

虽然这段代码并不适合你想做的事情，但你需要更改这些行

if num>0:
    l+='"'+ str(k) + '"=' + str(num)+' '
    True
if True:
    lst+=[l]

如果您将其更改为

if num>0:
    l+='"'+ str(k) + '"=' + str(num)+' '
    flag = True
if flag:
    lst+=[l]

然后如果你在for循环的开头重新初始化flag = False，它应该产生你想要的结果。通过执行if True，你要说的是总是附加到列表vs当那里有实际的东西时

如何修改输出

1 个答案: