Question

我想将以下消息除以10个字符。我想将每个部分都附加到StringBuilder对象中。

    04421,1,13,S,312|4000004130,1;4000000491,1;4000005240,1;4000005789,2;4000004978,2;4000004934,2;4000004936,1;4000000569,2;4000005400,1;4000000;4000004934,2;

我已经完成了以下解决方案：

    if(getMsgOtherPart(message) != null){      
         System.out.println("part message::"+getMsgOtherPart(message));
         String newMessage = getMsgOtherPart(message) ;

        int len = newMessage.length();
         System.out.println("len::"+len);
        int firstIndex = 0;
        int limit = 10;
        int lastIndex = 10;
        int count = 0;
        StringBuilder sb = new StringBuilder();
        String completeMessage = null;
        for(int i = 0; i <= len;i++){
            count++;
            if( count == limit  && lastIndex < len){
                sb.append(getSmsUniqueHeader());
                sb.append(newMessage.substring(firstIndex,lastIndex));
                sb.append("#"); 
                sb.append("\n");                   
                firstIndex = lastIndex;
                lastIndex = firstIndex + limit;
                count = 0;
            } else if(count < limit && i == len)    {
                 System.out.println("lastIndex:: "+lastIndex);
                 sb.append(getSmsUniqueHeader());
                sb.append(newMessage.substring(lastIndex-10));
                sb.append("#"); 

            }               

        }
        completeMessage = sb.toString(); 
        System.out.println("message::\n"+completeMessage);
    }

我得到了输出：

message::
$04421,1,13#
$,S,312|400#
$0004130,1;#
$4000000491#
$;400000540#
$0,1;400000#
$0;40000000#
$63,1;40000#
$00076,1;40#
$00000776,2#
$;400000078#
$8,2;400000#
------------
$0;#

请让我知道优化我的解决方案。

Answer 1

我在我的一个项目中做过这种事情，这里是我使用的函数，它返回List但你可以修改它并使用StringBuilder。

public List<String> splitStringEqually(String txtStr, int subStringSize) {
    List<String> splittedStringList = new ArrayList<String>();
    for (int start = 0; start < txtStr.length(); start += subStringSize) {

        splittedStringList.add(txtStr.substring(start, Math.min(txtStr.length(), start + subStringSize)));
    }
    return splittedStringList;
}

Answer 2

您可以使用Google的Guava库并使用Splitter类。

   StringBuilder sb=new StringBuilder();
    for(String s: Splitter.fixedLength(10).split(message)){
        sb.append(s);
        sb.append("#\n");
    }
    System.out.println(sb.toString());

Answer 3

字符串在内部维护为char数组。您可以使用message.toCharArray()获取该char数组的副本，并使用简单的循环或java 8流选择10块的元素，并执行您需要执行的任何操作。

Answer 4

严重依赖https://graph.microsoft.io/en-us/docs/authorization/app_authorization并解决来自OP的特定请求，代码可能看起来像这样（请注意那个，请不要这个！）：

public String splitStringEqually(String txtStr, int subStringSize) {
    // Start off with the header
    StringBuilder sb = new StringBuilder("message::\n");

    int len = txtStr.length();
    for (int start = 0; start < len; start += subStringSize) {
        sb.append("$");
        // Copy the next 10 characters, or less if at end of string
        // Does not use txtStr.substring() as that creates an
        // unnecessary temporary string
        sb.append(txtStr, start, Math.min(len, start + subStringSize));
        sb.append("#\n");
    }

    return sb.toString();
}

这可以简单地调用：

String completeMessage = splitStringEqually(newMessage, limit);

字符串消息按字符划分10个字符

4 个答案: