如果我有一张像
这样的表格recognizer.setKeywordThreshold(1e-40f)
我如何计算总体喜欢但按客户分组,所以我最终得到的结果如下:
customer liked
1 true
2 true
3 true
1 true
2 false
答案 0 :(得分:2)
GROUP BY
和条件COUNT
应该:
SELECT customer, COUNT(CASE WHEN liked = 'true' THEN 1 END) AS likes
FROM yourtable
group by customer
如果它是布尔列,请执行:
SELECT customer, COUNT(CASE WHEN liked THEN 1 END) AS likes
FROM yourtable
group by customer
答案 1 :(得分:2)
在Postgres中,您可以使用简写从布尔值转换为整数:
select customer, sum(liked::int) as total_likes
from t
group by customer;
请注意,这将返回所有客户,而不仅仅是那些喜欢的客户。如果您只想要喜欢的客户,那么where
子句是合适的:
select customer, count(*)
from t
where liked
group by customer;
答案 2 :(得分:1)
ng-class="{className:[condition]}"
ng-class="{custom-directive:[value =='ABC']}"
答案 3 :(得分:1)
我假设SELECT customer, COUNT(liked) AS total_likes
FROM table_name
WHERE liked is true
GROUP BY customer
是一个布尔类型字段,
ids = @anonymous.ids
ids.concat(@amitian.ids) if amitian_signed_in?
@confessions = Confession.where(amitian_id: ids).order('created_at DESC')
答案 4 :(得分:0)
在CASE
函数中使用COUNT
语句。
SELECT customer, COUNT(CASE WHEN liked = 'true' THEN 1 ELSE NULL END) AS total_likes
FROM yourtable