Question

我正在尝试将管理应用中的外键选项限制为特定用户（我尝试限制的字段称为学校）。这就是我的代码的样子 - 不幸的是，当我尝试编辑学生时（通过点击他们的名字），有两个问题（如下所述）。

1.学校的默认值是 -

2.当我从下拉菜单中选择合适的学校并尝试保存时，我会在校园里收到错误

选择有效的选择。这种选择不是可用的选择之一选择。

这就是它的样子

class modelStudentAdmin(admin.ModelAdmin):   

     def get_queryset(self, request):
        qs = super(modelStudentAdmin, self).get_queryset(request)

        if request.user.is_superuser:
            return qs
        else:
            schoolInstance = modelSchool.objects.get(user=request.user)
            qs = modelStudent.objects.filter(school=schoolInstance)
            return qs

    def formfield_for_foreignkey(self, db_field, request, **kwargs):
        if request.user.is_superuser:
            return super(modelStudentAdmin, self).formfield_for_foreignkey(db_field, request, **kwargs)

        #Not superuser only staff
        if db_field.name == 'school':
            t = modelSchool.objects.filter(user=request.user).values_list("school_name",flat=True)
            kwargs['queryset'] = t

        return super(modelStudentAdmin,self).formfield_for_foreignkey(db_field, request, **kwargs)

现在，如果我删除方法

def formfield_for_foreignkey(self, db_field, request, **kwargs):

一切正常但我不能限制外键。关于我可能做错什么的任何建议？

Answer 1

尝试替换

@Getter
@Setter
@Entity
@EqualsAndHashCode
@Table(name = "produto")
@IdClass(ProdutoId.class)
public class Produto implements Serializable {

    private static final long serialVersionUID = 1L;

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "id_produto")
    private Long idProduto;

    @Id
    @Column(name = "oficina", insertable = false, updatable = false)
    private Long idOficina;

    @ManyToOne
    @JoinColumn(name = "oficina")
    private Oficina oficina;

}



@AllArgsConstructor
@NoArgsConstructor
@EqualsAndHashCode
@Data
public class ProdutoId implements Serializable {

    public Long idProduto;
    public Long idOficina;

}


@Repository
public interface ProdutoRepository extends JpaRepository<Produto, ProdutoId> {}

用这个

import org.springframework.core.convert.converter.Converter;

public class BuildingIdToBuildingConverter implements Converter<String, Building> {

    private BuildingService buildingService;

    public BuildingIdToBuildingConverter(BuildingService buildingService) {
        this.buildingService = buildingService;
    }

    @Override
    public Building convert (String id) {
            return buildingService.getBuilding(id);
    }
}

您不需要value_list您的查询集。

限制ModelAdmin中的外键选项返回“选择有效选项”

1 个答案: