在我的应用程序中,我有一个下拉列表(部门),该下拉列表取决于先前从下拉列表(“教职”字段)中选择的值。我正在使用ajax获得可以正常工作的新值。但是,当我尝试保存表单时,我得到选择一个有效的选择。该选择不是可用的选择之一。
这是我的模特
from django.db import models
from system.models import FacultyData, DepartmentData, SessionData, SemesterData, SettingsData
# Create your models here.
class SchoolFees(models.Model):
fid = models.ForeignKey(FacultyData, on_delete= models.SET_NULL, null=True)
did = models.ForeignKey(DepartmentData, on_delete= models.SET_NULL, null=True)
sid = models.ForeignKey(SessionData, on_delete= models.SET_NULL, null=True)
amount = models.CharField(max_length=30)
def __str__(self):
return self.amount
和我的form.py
from django import forms
from . import models
from system.models import FacultyData, DepartmentData, SessionData
from .models import SchoolFees
class FeesCreationForm(forms.ModelForm):
fid = forms.ModelChoiceField(queryset=FacultyData.objects.all(), empty_label="--Select Faculty--",
widget=forms.Select(attrs={'class': 'form-control'}))
did = forms.ModelChoiceField(queryset=DepartmentData.objects.all(), empty_label="--Select Faculty First--",
widget=forms.Select(attrs={'class': 'form-control'}))
sid = forms.ModelChoiceField(queryset=SessionData.objects.all(), empty_label="--Select Session--",
widget=forms.Select(attrs={'class': 'form-control'}))
class Meta:
model = models.SchoolFees
fields = ['sid', 'fid', 'did', 'amount']
widgets = {
'amount': forms.TextInput(attrs={'class': 'form-control', 'placeholder': 'Enter Amount'})
}
def __init__(self, *args, **kwargs):
super(FeesCreationForm, self).__init__(*args, **kwargs)
self.fields['did'].queryset = DepartmentData.objects.none()
# Get did queryset for the selected fid
if 'fid' in self.data:
try:
fd = int(self.data.get('fid'))
self.fields['did'].queryset = DepartmentData.objects.filter(fid=fd).order_by('dept_name')
except (ValueError, TypeError):
pass # invalid input from the client; ignore and use empty queryset
在我的view.py中,我有一种根据所选择的系获取科系的方法。以及节省新费用
def create_fee(request):
app = settings.CONFIG
#table = FacultyTable(FacultyData.objects.all())
# RequestConfig(request, paginate={'per_page': 10}).configure(table)
context = {"form": FeesCreationForm, 'app': app}
return render(request, 'bursary.html', context)
def get_department(request):
fid = request.GET.get('fid', None)
datas = {
'is_taken': DepartmentData.objects.filter(fid=fid)
}
department = list(DepartmentData.objects.filter(fid=fid).values())
data = dict()
data['department'] = department
return JsonResponse(data)
def save_fee(request):
app = settings.CONFIG
# table = FacultyTable(FacultyData.objects.all())
# RequestConfig(request, paginate={'per_page': 10}).configure(table)
form = FeesCreationForm(request.POST)
context = {"form": FeesCreationForm, 'app': app}
if form.is_valid():
form.save()
messages.add_message(request, messages.SUCCESS, "Fees added successfully")
else:
messages.add_message(request, messages.ERROR, form.errors)
return redirect('bursary:create_fee')
我不知道我在哪里弄错了或者怎么解决
答案 0 :(得分:1)
这是因为您将查询集初始化为空(这很好),但决不要在表单对象本身内对其进行更新。因此服务器端验证失败。
尝试在FeesCreationForm的__init__
方法中更新查询集:
def __init__(self, *args, **kwargs):
super().__init__(*args, **kwargs)
# Init empty did queryset
self.fields['did'].queryset = DepartmentData.objects.none()
# Get did queryset for the selected fid
if 'fid' in self.data:
try:
fid = int(self.data.get('fid'))
self.fields['did'].queryset = DepartmentData.objects.filter(
fid=fid).order_by()
except (ValueError, TypeError):
# invalid input from the client; ignore and use empty queryset
pass
答案 1 :(得分:1)
(解释)
我有一个下拉菜单,具体取决于先前从另一个下拉菜单中选择的值
我过去也有类似的问题。 this是否回答您的问题?基本思想是,您可以将所有正确的信息发送到所需的客户端,但是在一天结束时,服务器应验证是否使用了正确的选项集。 Django生气了,因为它认为发送到服务器的第二个下拉列表选择无效。收到POST后,您需要根据作为下拉列表#1的选择发送的内容动态地获得第二个下拉列表的选择,然后尝试验证表单。