我有这段代码:
import numpy as np
class Variables(object):
def __init__(self, var_name, the_method):
self.var_name = var_name
self.the_method = the_method
def evaluate_v(self):
var_name, the_method = self.var_name, self.the_method
if the_method == 'diff':
return var_name[0] - var_name[1]
和这个测试代码:
import unittest
import pytest
import numpy as np
from .variables import Variables
class TestVariables():
@classmethod
def setup_class(cls):
var_name = np.array([[1, 2, 3], [2, 3, 4]])
the_method = 'diff'
cls.variables = Variables(var_name, the_method)
@pytest.mark.parametrize(
"var_name, the_method, expected_output", [
(np.array([[1, 2, 3], [2, 3, 4]]), 'diff', np.array([-1, -1, -1]) ),
])
def test_evaluate_v_method_returns_correct_results(
self, var_name, the_method,expected_output):
var_name, the_method = self.variables.var_name, self.variables.the_method
obs = self.variables.evaluate_v()
assert obs == expected_output
if __name__ == "__main__":
unittest.main()
我想计算第一个和最后一个元素之间的差异。
结果应为数组[-1, -1, -1]
。
如果我尝试运行测试,它会给我:
ValueError: The truth value of an array with more than one element is ambiguous.
Use a.any() or a.all()
在我的情况下,我不确定如何使用(如果必须的话)np.all()
。
答案 0 :(得分:0)
assert np.all(obs == expected_output)
有效:
def test_evaluate_v_method_returns_correct_results(
self, var_name, the_method,expected_output):
var_name, the_method = self.variables.var_name, self.variables.the_method
obs = self.variables.evaluate_v()
assert np.all(obs == expected_output)
测试它:
py.test np_test.py
================================== test session starts ===================================
platform darwin -- Python 3.5.2, pytest-2.9.2, py-1.4.31, pluggy-0.3.1
rootdir: /Users/mike/tmp, inifile:
plugins: hypothesis-3.4.0, asyncio-0.4.1
collected 1 items
np_test.py .
================================ 1 passed in 0.10 seconds ================================