JSONSerialization返回错误,但是php parcer

时间:2017-01-27 11:03:34

标签: json swift serialization swift3 jsonserializer

我从服务器收到一个JSON字符串,它看起来像这样:

[[{\"type\":\"action\",\"action\":\"courier_on_map\",\"text\":\"\\u0421\\u043c\\u043e\\u0442\\u0440\\u0435\\u0442\\u044c \\u043d\\u0430 \\u043a\\u0430\\u0440\\u0442\\u0435\"}]]

Web解析器说“JSON字符串有效,但JSON数据不准确”。然而,JSONSerialization说:

字符1周围的对象中的值没有字符串键

并返回错误。

代码:

    func convertToNSDictionary() -> NSDictionary?
    {
        var string = self
        string = string.replacingOccurrences(of: "[", with: "")
        string = string.replacingOccurrences(of: "]", with: "")

        if let data = string.data(using: .utf8) {
            do {
                return try JSONSerialization.jsonObject(with: data, options: []) as? NSDictionary
            } catch {
                print(error.localizedDescription)
            }
        }

        return nil
    }

1 个答案:

答案 0 :(得分:0)

不要手动操作原始JSON字符串。

假设您的代码位于String的扩展名内,请执行以下操作:

let str = "[[{\"type\":\"action\",\"action\":\"courier_on_map\",\"text\":\"\\u0421\\u043c\\u043e\\u0442\\u0440\\u0435\\u0442\\u044c \\u043d\\u0430 \\u043a\\u0430\\u0440\\u0442\\u0435\"}]]"

extension String {
    func convertToDictionary() -> [String:Any]? {
        let str = self

        guard let data = str.data(using: .utf8),
              let json = try? JSONSerialization.jsonObject(with: data, options: []) as! [[[String:Any]]]
        else {
            return nil
        }

        //debug prints
        print(json)
        let innerArray = json.first!
        print(innerArray)
        let dict = innerArray.first!
        print(dict)
        if let type = dict["type"] {
            print(type)
        }
        //

        return dict
    }
}

let dict = str.convertToDictionary()

print(dict)

打印:

[[["type": action, "action": courier_on_map, "text": Смотреть на карте]]]
[["type": action, "action": courier_on_map, "text": Смотреть на карте]]
["type": action, "action": courier_on_map, "text": Смотреть на карте]
action
Optional(["type": action, "action": courier_on_map, "text": Смотреть на карте])

如果你真的需要一个NSObject,你可以施展它:

let nsDict = dict! as NSDictionary