Question

我正在调用我的注册服务，其中参数正常，url也正确，我得到状态代码200作为响应，但是当我打印结果和响应时，它显示失败。我已经检查了所有注册所需的一切看起来很好，但我很困惑为什么它显示失败的回应。它显示了这一点，

["FirstName": "Awais", "Email": "awais@gmail.com", "PhoneNumber": "08965235415", "Password": "123456", "LastName": "Ahmed", "ConfirmPassword": "123456"]
Request: Optional(MyURL)
Response: Optional(<NSHTTPURLResponse: 0x604000438900> { URL: http://api.theahsanzaman.info/api/Account/Register } { Status Code: 200, Headers {
"Cache-Control" =     (
    "no-cache"
);
"Content-Length" =     (
    0
);
Date =     (
    "Tue, 17 Apr 2018 13:37:03 GMT"
);
Expires =     (
    "-1"
);
Pragma =     (
    "no-cache"
);
Server =     (
    "Microsoft-IIS/8.5"
);
"X-AspNet-Version" =     (
    "4.0.30319"
);
"X-Powered-By" =     (
    "ASP.NET"
);
"X-Powered-By-Plesk" =     (
    PleskWin
);
} })  


Result: FAILURE
RR FAILURE: responseSerializationFailed(Alamofire.AFError.ResponseSerializationFailureReason.inputDataNilOrZeroLength)
0

1111
"FAILURE: responseSerializationFailed(Alamofire.AFError.ResponseSerializationFailureReason.inputDataNilOrZeroLength)"

我的请求代码就是这个，

import SwiftyJSON
import Alamofire
import UIKit

class SignUpService{

    static let instance = SignUpService()
    var status = 0

    func signUpUser(param:[String: String],completion:@escaping CompletionHandler)  {

        let url = URL.init(string: SignUpUrl)
        Alamofire.request(url!, method: .post, parameters: param, encoding:JSONEncoding.default, headers: nil).responseJSON { (response) in
            print("Request: \(String(describing: response.request))")   // original url request
            print("Response: \(String(describing: response.response))") // http url response
            print("Result: \(response.result)")// response serialization result
            print("RR \(response)")

            if response.result.error == nil{
                self.status = (response.response?.statusCode)!
                if(self.status == 200){
                    print("successful")

                }
                completion(true)
                print("11112222")
            }else{
                completion(false)
                print("1111")
                debugPrint(response.description as Any)
            }
        }
    }
}

我很困惑，如果状态代码为200，为什么它没有显示响应成功。

Answer 1

通过在alamofire请求中添加validate（statusCode：200 ..＆lt; 299）来调用API时验证响应状态代码。

如果成功代码为200，您的代码将会成功。

    Alamofire.request(url!, method: .post, parameters: param, encoding:JSONEncoding.default, headers: nil). validate(statusCode: 200..<300).responseJSON { (response) in

        switch response.result {
        case .success(let data): 
            Logs.DLog(object: "\n Success: \(response)")

            // Do your code here...

        case .failure(let error):
            Logs.DLog(object: "\n Failure: \(error.localizedDescription)")

            // Do your code here...

        }
    })

但是你没有得到响应JSON，所以你无法解码响应JSON。

在swift中使用Alamofire的JsonSerialization错误

1 个答案: