如何在Java中的for循环中打印for循环

时间:2017-01-27 02:56:29

标签: java for-loop random formatting

Java初学者。但是有C和Python的历史。

我正在尝试使用此代码:

package javaman;
import java.util.Random;
public class JavaMan{


    public static void main(String[] args) {
        Random random = new Random();
        int randomInteger = 0;
        float average = 0;
        System.out.println("The 3 Numbers are:");
        for (int i=0; i<3; i++) {
            randomInteger = random.nextInt(51);
            System.out.println(randomInteger);
            average = average + randomInteger;
        }
        average = average/3;
        System.out.println("The average of the three random numbers (between 0-50) is: " + average);
    }
}

并使其打印出以下内容:

The 3 Numbers are: 
Number 1 is: 32
Number 2 is: 16
Number 3 is: 0
The average of the three random numbers (between 0-50) is: 16.0

然而,我已经编程了这样,每当我使用randomInteger时,它只是在我希望for循环有自己的for循环时运行整个for循环(整个“Number x is:”不存在...它只是打印3个数字并吐出平均值):从某种意义上说,我会像以下那样......

("Number", i, "is:", randomInteger) this would look like "Number 1 is: 16"
("Number", i, "is:", randomInteger) this would look like "Number 2 is: 15"
("Number", i, "is:", randomInteger) etc.  

如何在Java中创建它?

1 个答案:

答案 0 :(得分:1)

只需添加System.out.println ("Number "+i+" is:"+randomInteger);

即可
 public static void main(String[] args) {
    Random random = new Random();
    int randomInteger = 0;
    float average = 0;
    System.out.println("The 3 Numbers are:");
    for (int i=0; i<3; i++) {
        randomInteger = random.nextInt(51);
        //  System.out.println(randomInteger);
        System.out.println ("Number "+i+" is:"+randomInteger);
        average = average + randomInteger;
    }
    average = average/3;
    System.out.println("The average of the three random numbers (between 0-50) is: " + average);
}