在python循环中打印

Question

我有两个列表，例如：

img*=(4095/65535.);

并且为了生成脚本，我需要打印它们，例如：

list1=["read1","read2","read3"]
list2=["read4","read5","read6"]

我尝试过：

Programm -h -y -1 $read1,$read2,$read3 -2 $read4,$read5,$read6

但是它确实可以工作，有人有想法吗？

Answer 1

不确定要隐含的意图，但是它可能很简单：

List1 = ['read1', 'read2', 'read3']
List2 = ['read4', 'read5', 'read6']

List1 = ["$"+(i) for i in List1]
List2 = ["$"+(i) for i in List2]

print('Programm -h -y -1', end=" ")
print(",".join(List1) + " -2 " + ",".join(List2))

编辑：

甚至更好，谢谢@Matt B。

List1 = ['read1', 'read2', 'read3']
List2 = ['read4', 'read5', 'read6']

print("Programm -h -y -1 " + "$" + ",$".join(List1) + " -2 $" + ",$".join(List2))

输出：

Programm -h -y -1 $read1,$read2,$read3 -2 $read4,$read5,$read6

Answer 2

使用$在列表中添加list-comprehension，然后使用join从list创建一个字符串。

List1=['read1','read2','read3']
List2=['read4','read5','read6']

List1 = ["$"+str(i) for i in List1]
List2 = ["$"+str(i) for i in List2]

x = "Programm -h -y -1 {} -2 {}".format(",".join(List1), ",".join(List2))

print(x)

输出：

Programm -h -y -1 $read1,$read2,$read3 -2 $read4,$read5,$read6