我正在为调查目的做一个简单的任务。问题如下:
现在我可以建造一棵树了。这个方法做到了:
private readonly Stack<Expression> expressionStack = new Stack<Expression>();
private readonly Stack<Symbol> operatorStack = new Stack<Symbol>();
private readonly List<string> parameters = new List<string>();
public Expression<Func<decimal[], decimal>> Parse(string expression)
{
if (string.IsNullOrWhiteSpace(expression))
{
return s => 0;
}
var arrayParameter = Expression.Parameter(typeof(decimal[]), "args");
parameters.Clear();
operatorStack.Clear();
expressionStack.Clear();
using (var reader = new StringReader(expression))
{
int peek;
while ((peek = reader.Peek()) > -1)
{
var next = (char)peek;
if (char.IsDigit(next))
{
expressionStack.Push(ReadOperand(reader));
continue;
}
if (char.IsLetter(next))
{
expressionStack.Push(ReadParameter(reader, arrayParameter));
continue;
}
if (Operation.IsDefined(next))
{
if (next == '-' && expressionStack.Count == 0)
{
reader.Read();
operatorStack.Push(Operation.UnaryMinus);
continue;
}
var currentOperation = ReadOperation(reader);
EvaluateWhile(() => operatorStack.Count > 0 && operatorStack.Peek() != Parentheses.Left &&
currentOperation.Precedence <= ((Operation)operatorStack.Peek()).Precedence);
operatorStack.Push(currentOperation);
continue;
}
if (next == '(')
{
reader.Read();
operatorStack.Push(Parentheses.Left);
if (reader.Peek() == '-')
{
reader.Read();
operatorStack.Push(Operation.UnaryMinus);
}
continue;
}
if (next == ')')
{
reader.Read();
EvaluateWhile(() => operatorStack.Count > 0 && operatorStack.Peek() != Parentheses.Left);
operatorStack.Pop();
continue;
}
if (next == ' ')
{
reader.Read();
}
else
{
throw new ArgumentException(string.Format("Encountered invalid character {0}", next),
"expression");
}
}
}
EvaluateWhile(() => operatorStack.Count > 0);
return Expression.Lambda<Func<decimal[], decimal>>(expressionStack.Pop(), arrayParameter);
}
此方法有效,并返回预期结果 在发送到服务器之前,我想将树序列化为二进制类型。我的问题如下。这是我申请的最简单的方法吗? 我找到了许多LINQ序列化的解决方案,但它们太大了。我不需要这些解决方案的全部功能。另外,通常,它们提供JSON或XML序列化,但我需要二进制序列化。 有人可以为这个问题建议一个简单易行的解决方案吗?