Question

Q值。做一个名为餐厅的课程。 Restaurant的 init （）方法应存储两个属性：restaurant_name和cuisine_type。创建一个名为describe_restaurant（）的方法来打印这两条信息，以及一个名为open_restaurant（）的方法，它打印一条消息，表明餐厅是开放的。从您的班级创建一个名为restaurant的实例。单独打印两个属性，然后调用这两种方法。

big chill
italian
Traceback (most recent call last):
  File "/Users/rishabhchopra/Desktop/practice2/9-1.Restaurant.py", line 21, in <module>
    restaurant1.describe_restaurant()
AttributeError: 'Restaurant' object has no attribute 'describe_restaurant'
[Finished in 0.1s with exit code 1]

我得到的输出为：

<script>
    var phpParams = <?php echo json_encode($jsParams); ?>;
</script>

问：为什么Python会将我的类的方法解释为属性？

Answer 1

假设你的缩进真的像这样

 class Restaurant():
    """An attempt to model a restaurant"""

    def __init__(self,restaurant_name,cuisine_type):
        """Initializing name and age attributes"""
        self.name = restaurant_name
        self.cuisine  = cuisine_type

        def describe_restaurant(self):
            # Describes the restaurant name and cuisine
            print(self.name.title() + " serves " + self.cuisine + " food.")

        def open_restaurant(self):
            # Opens the restaurant and welcomes customers.
            print(self.name.title() + " is now Open. \nCome. \nHave some delicious " + self.cuisine + "

您在__init__方法中意外嵌套了所需的方法，使其无法访问。修复嵌套，你不应该有任何问题。

 class Restaurant():
    """An attempt to model a restaurant"""

    def __init__(self,restaurant_name,cuisine_type):
        """Initializing name and age attributes"""
        self.name = restaurant_name
        self.cuisine  = cuisine_type

    def describe_restaurant(self):
        # Describes the restaurant name and cuisine
        print(self.name.title() + " serves " + self.cuisine + " food.")

    def open_restaurant(self):
        # Opens the restaurant and welcomes customers.
        print(self.name.title() + " is now Open. \nCome. \nHave some delicious " + self.cuisine + "

请注意，方法是cdarke提到的属性 - 错误消息非常清楚。

Answer 2

纠正你的缩进，它工作正常：

class Restaurant():
    """An attempt to model a restaurant"""

    def __init__(self,restaurant_name,cuisine_type):
        """Initializing name and age attributes"""
        self.name = restaurant_name
        self.cuisine  = cuisine_type

    def describe_restaurant(self):
        # Describes the restaurant name and cuisine
        print(self.name.title() + " serves " + self.cuisine + " food.")

    def open_restaurant(self):
        # Opens the restaurant and welcomes customers.
        print(self.name.title() + " is now Open. \nCome. \nHave some delicious " + self.cuisine + " food.")

restaurant1 = Restaurant("big chill","italian")

print(restaurant1.name)
print(restaurant1.cuisine)
restaurant1.describe_restaurant()

顺便说一下，方法是属性。

Answer 3

它只是缩进。

class Restaurant():

 def __init__(self,restaurant_name,cuisine_type):
      self.name = restaurant_name
      self.cuisine  = cuisine_type

 def describe_restaurant(self):
    # Describes the restaurant name and cuisine
    print(self.name.title() + " serves " + self.cuisine + " food.")

 def open_restaurant(self):
    # Opens the restaurant and welcomes customers.
    print(self.name.title() + " is now Open. \nCome. \nHave some delicious " + self.cuisine + " food.")
restaurant1 = Restaurant("big chill","italian")

print(restaurant1.name)
print(restaurant1.cuisine)
restaurant1.describe_restaurant()

AttributeError：'Restaurant'对象没有属性'describe_restaurant'

3 个答案: