UPDATE sql for DB2中的INNER JOIN

时间:2010-11-15 12:15:29

标签: sql db2

有没有办法在DB2的update语句中使用连接?

谷歌真的让我失望了

这大致是我想要实现的目标(......除了明显的工作......)

update file1 inner join file2                                 
       on substr(file1.firstfield,10,20) = substr(file2.anotherfield,1,10)                                                                    
set file1.firstfield = ( 'BIT OF TEXT' concat file2.something )                                                                             
where file1.firstfield like 'BLAH%'                             

干杯

9 个答案:

答案 0 :(得分:8)

您没有说明您要定位的平台。但是,将表作为文件引用,使我相信您不是在Linux,UNIX或Windows(LUW)上运行DB2。

但是,如果您在DB2 LUW上 ,请参阅MERGE声明:

对于您的示例语句,这将写为:

merge into file1 a
   using (select anotherfield, something from file2) b
   on substr(a.firstfield,10,20) = substr(b.anotherfield,1,10)
when matched and a.firstfield like 'BLAH%'
   then update set a.firstfield = 'BIT OF TEXT' || b.something;

请注意:对于DB2,SUBSTR函数的第三个参数是要返回的字节数,而不是结束位置。因此,SUBSTR(a.firstfield,10,20)返回CHAR(20)。但是,SUBSTR(b.anotherfield,1,10)返回CHAR(10)。我不确定这是否是故意的,但可能会影响你的比较。

答案 1 :(得分:7)

update语句中的联接是非标准的,并非所有供应商都支持。您尝试做的事情可以通过子选择完成:

update
  file1
set
  firstfield = (select 'stuff' concat something from file2 where substr(file1.field1, 10, 20) = substr(file2.xxx,1,10) )
where
  file1.foo like 'BLAH%'

答案 2 :(得分:6)

试试这个,然后告诉我结果:

UPDATE File1 AS B                          
SET    b.campo1 = (SELECT DISTINCT A.campo1
                   FROM  File2 A           
                   INNER JOIN File1      
                   ON A.campo2 = File1.campo2 
                   AND A.campo2 = B.campo2) 

答案 3 :(得分:3)

这是我刚刚开始工作的一个很好的例子:

update cac c
set ga_meth_id = (
    select cim.ga_meth_id 
    from cci ci, ccim cim 
    where ci.cus_id_key_n = cim.cus_id_key_n
    and ci.cus_set_c = cim.cus_set_c
    and ci.cus_set_c = c.cus_set_c
    and ci.cps_key_n = c.cps_key_n
)
where exists (
    select 1  
    from cci ci2, ccim cim2 
    where ci2.cus_id_key_n = cim2.cus_id_key_n
    and ci2.cus_set_c = cim2.cus_set_c
    and ci2.cus_set_c = c.cus_set_c
    and ci2.cps_key_n = c.cps_key_n
)

答案 4 :(得分:3)

更新回答https://stackoverflow.com/a/4184237/565525

如果您想要多列,可以像这样实现:

update file1
set
  (firstfield, secondfield) = (
        select 'stuff' concat 'something from file2', 
               'some secondfield value' 
        from file2
        where substr(file1.field1, 10, 20) = substr(file2.xxx,1,10) )
where
  file1.foo like 'BLAH%'

来源:http://www.dbforums.com/db2/1615011-sql-update-using-join-subquery.html#post6257307

答案 5 :(得分:1)

只更新符合条件的行,并避免更新其他行中的空值:

update table_one set field_1 = 'ACTIVE' where exists 
(select 1 from table_two where table_one.customer = table_two.customer);

它适用于DB2 / AIX64 9.7.8

答案 6 :(得分:0)

DB2 LUW 9.7上the UPDATE statement的参考文档提供了以下示例:

   UPDATE (SELECT EMPNO, SALARY, COMM,
     AVG(SALARY) OVER (PARTITION BY WORKDEPT),
     AVG(COMM) OVER (PARTITION BY WORKDEPT)
     FROM EMPLOYEE E) AS E(EMPNO, SALARY, COMM, AVGSAL, AVGCOMM)
   SET (SALARY, COMM) = (AVGSAL, AVGCOMM)
   WHERE EMPNO = '000120'

UPDATE后的括号可以包含一个完整的选择,这意味着任何有效的SELECT语句都可以去那里。

基于此,我建议如下:

UPDATE (
  SELECT
    f1.firstfield,
    f2.anotherfield,
    f2.something
  FROM file1 f1
  WHERE f1.firstfield like 'BLAH%' 
  INNER JOIN file2 f2
  ON substr(f1.firstfield,10,20) = substr(f2.anotherfield,1,10)
)
AS my_files(firstfield, anotherfield, something)
SET
  firstfield = ( 'BIT OF TEXT' || something )

编辑:伊恩是对的。我的第一直觉是尝试使用subselects:

UPDATE file1 f1
SET f1.firstfield = ( 'BIT OF TEXT' || (
  SELECT f2.something
  FROM file2 f2
  WHERE substr(f1.firstfield,10,20) = substr(f2.anotherfield,1,10)
))
WHERE f1.firstfield LIKE 'BLAH%' 
AND substr(f1.firstfield,10,20) IN (
  SELECT substr(f2.anotherfield,1,10)
  FROM file2 f2
)

但我不确定连接是否有效。它还假设子串之间存在1:1的映射。如果有多个匹配的行,则无效。

答案 7 :(得分:0)

你问

update file1 f1
set file1.firstfield=
(
select 'BIT OF TEXT' || f2.something
from file2 f2
where substr(f1.firstfield,10,20) = substr(f2.anotherfield,1,10)
)
where exists
(
select * from file2 f2
where substr(f1.firstfield,10,20) = substr(f2.anotherfield,1,10)
)
and f1.firstfield like 'BLAH%'

如果连接给出多个结果,您可以像这样强制更新

update file1 f1
set file1.firstfield=
(
select 'BIT OF TEXT' || f2.something
from file2 f2
where substr(f1.firstfield,10,20) = substr(f2.anotherfield,1,10)
fetch first rows only
)
where exists
(
select * from file2 f2
where substr(f1.firstfield,10,20) = substr(f2.anotherfield,1,10)
)
and f1.firstfield like 'BLAH%' 

模板方法

update table1 f1
set (f1.field1, f1.field2, f1.field3, f1.field4)=
(
select f2.field1, f2.field2, f2.field3, 'CONSTVALUE'
from table2 f2
where (f1.key1, f1.key2)=(f2.key1, f2.key2) 
)
where exists 
(
select * from table2 f2
where (f1.key1, f1.key2)=(f2.key1, f2.key2)
) 

答案 8 :(得分:-3)

在标准SQL中,此类更新如下所示:

update a
   set a.firstfield ='BIT OF TEXT' + b.something
  from file1 a
  join file2 b
    on substr(a.firstfield,10,20) = 
       substr(b.anotherfield,1,10)
 where a.firstfield like 'BLAH%' 

通过较小的语法变体,这种类型的东西可以在Oracle或SQL Server上运行,并且(尽管我没有可用于测试的DB / 2实例)几乎肯定会在DB / 2上运行。