Question

我一直在与同行进行查询，并且一直在回转一些不寻常的数字。该查询是生产力报告。我正在尝试为特定最终用户计算所有可计费单位，将该总计与单个预期值进行比较，然后计算1周内这两个数字之间的差异。以下是我们迄今为止提出的建议：

SELECT
 Employees.emp_id,
 Employees.last_name+', '+Employees.first_name as staff_name,
 SUM(VisitQuery.billed_value)/60 AS billed_value,
 SUM(StandardQuery.num8) as expected_value
FROM
 Employees
INNER JOIN
(
  SELECT
   ClientVisit.duration AS billed_value,
   ClientVisit.emp_id,
   ClientVisit.client_id
  FROM
   ClientVisit
  WHERE
   ClientVisit.non_billable = 0 AND
   ClientVisit.rev_timeout >= @param1 AND
   ClientVisit.rev_timeout <= @param2
) VisitQuery
ON VisitQuery.emp_id = Employees.emp_id
INNER JOIN
(
 SELECT DISTINCT
  CaseloadQuery.emp_id,
  ClientsExt.num8
 FROM
 (
  SELECT
   ClientVisit.duration AS billed_value,
   ClientVisit.emp_id,
   ClientVisit.client_id
  FROM
   ClientVisit
  WHERE
   ClientVisit.non_billable = 0 AND
   ClientVisit.rev_timeout >= @param1 AND
   ClientVisit.rev_timeout <= @param2
 ) CaseloadQuery
 INNER JOIN ClientsExt
 ON CaseloadQuery.client_id = ClientsExt.client_id
) StandardQuery
ON Employees.emp_id = StandardQuery.emp_id
GROUP BY
 Employees.emp_id,
 Employees.last_name+', '+Employees.first_name`enter code here`

回报看起来像这样：

emp_id      staff_name      billed_value    expected_value
X           X               74              231
XX          XX              108             279
XXX         XXX             19              72

有没有人有任何想法？本周40小时的预期价值应该不高。

Answer 1

在表ClientVisit中，同一个员工（emp_id）是否有多行可以导致多个client_id值？如果答案是肯定的，那么我认为您还应该在GROUP BY

上进行client_id

下面我尝试重写您的查询（注意标有“添加”和“删除”的行。）

免责声明：我没有实际的数据库表来测试我的查询，所以它可能有语法和语义错误

SELECT
    Employees.emp_id,
    StandardQuery.client_id,                                        -- add 
    Employees.last_name+', '+Employees.first_name as staff_name,
    SUM(VisitQuery.billed_value)/60 AS billed_value,
    SUM(StandardQuery.num8) as expected_value
FROM
    Employees
    INNER JOIN
        (
            SELECT
                ClientVisit.duration AS billed_value,
                ClientVisit.emp_id,
                ClientVisit.client_id
            FROM
                ClientVisit
            WHERE
                ClientVisit.non_billable = 0 AND
                ClientVisit.rev_timeout >= @param1 AND
                ClientVisit.rev_timeout <= @param2
        ) VisitQuery 
        ON VisitQuery.emp_id = Employees.emp_id
    INNER JOIN
        (
            SELECT DISTINCT
                CaseloadQuery.emp_id,
                ClientsExt.num8,
                ClientsExt.client_id                                -- add
            FROM
                (
                    SELECT
                        -- ClientVisit.duration AS billed_value,    -- delete
                        ClientVisit.emp_id,
                        ClientVisit.client_id
                    FROM
                        ClientVisit
                    WHERE
                        ClientVisit.non_billable = 0 AND
                        ClientVisit.rev_timeout >= @param1 AND
                        ClientVisit.rev_timeout <= @param2
                )CaseloadQuery
                INNER JOIN ClientsExt 
                    ON CaseloadQuery.client_id = ClientsExt.client_id
        )StandardQuery 
            ON Employees.emp_id = StandardQuery.emp_id
GROUP BY
    Employees.emp_id, 
    -- Employees.last_name+', '+Employees.first_name                -- delete
    StandardQuery.client_id                                         -- add

SQL查询总数与单个值

1 个答案: