如何在连续循环中使用python多处理池

时间:2017-01-24 11:31:49

标签: python selenium-webdriver python-multiprocessing

我正在使用python多处理库来执行selenium脚本。我的代码如下:

#-- start and join multiple threads ---
thread_list = []
total_threads=10 #-- no of parallel threads
for i in range(total_threads):
    t = Process(target=get_browser_and_start, args=[url,nlp,pixel])
    thread_list.append(t)
    print "starting thread..."
    t.start()

for t in thread_list:
    print "joining existing thread..."
    t.join()

据我了解join()函数,它将等待每个进程完成。但我希望只要一个进程发布,它就会被分配另一个任务来执行新功能。

可以这样理解:

假设第一个实例启动了8个进程。

no_of_tasks_to_perform = 100

for i in range(no_of_tasks_to_perform):
    processes start(8)
    if process no 2 finished executing, start new process
    maintain 8 process at any point of time till 
    "i" is <= no_of_tasks_to_perform

1 个答案:

答案 0 :(得分:2)

不是偶尔启动新进程,而是尝试将所有任务放入multiprocessing.Queue(),并启动8个长时间运行的进程,在每个进程中继续访问任务队列获得新任务然后完成工作,直到不再有任务为止。

在你的情况下,它更像是这样:

from multiprocessing import Queue, Process

def worker(queue):
    while not queue.empty():
        task = queue.get()

        # now start to work on your task
        get_browser_and_start(url,nlp,pixel) # url, nlp, pixel can be unpacked from task

def main():
    queue = Queue()

    # Now put tasks into queue
    no_of_tasks_to_perform = 100

    for i in range(no_of_tasks_to_perform):
        queue.put([url, nlp, pixel, ...]) 

    # Now start all processes
    process = Process(target=worker, args=(queue, ))
    process.start()
    ...
    process.join()