Question

cI有一个我需要阅读的XML文件，它看起来与此类似：

<?xml version="1.0" encoding="UTF-8"?>
<flowers>
    <flower name="rose">
        <soilType>Podzolic</soilType>   
        <visualParameters>
            <stemColor>Green</stemColor>
            <leafColor>Red</leafColor>
            <averageSize>50</averageSize>
        </visualParameters>
    <growingTips>
            <LightType>photophilous</LightType>
            <temperature>38</temperature>
            <watering>1200</watering>
        </growingTips>
    <multiplying>bySeeds</multiplying>
    <origin>Belarus</origin>
        <description>Classic Choice</description>
    </flower>
</flowers>

在构建时，我使用JAXB为XSD生成我的类（此xsd由几列修改）。当我尝试验证它时，它会抱怨

无法解析名字＆＃39;鲜花＆＃39;到A（n）＆＃39;类型定义＆＃39;成分

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<xs:schema version="1.0" xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xs:element name="flowers" type="Flowers"></xs:element>

<xs:complexType name="flowers">
   <xs:sequence>
     <xs:element name="flower" type="flower" maxOccurs="unbounded" />
   </xs:sequence>
 </xs:complexType>

   <xs:element name="flower" type="FlowerType"/>
 <xs:complexType name="flower">
    <xs:sequence>
      <xs:element name="soilType" type="SoilType" minOccurs="0"/>
      <xs:element name="visualParameters" type="VisualParameters" minOccurs="0"/>
      <xs:element name="growingTips" type="growingTips" minOccurs="0"/>
      <xs:element name="multiplyingType" type="multiplyingType" minOccurs="0"/>
      <xs:element name="origin" type="xs:string" minOccurs="0"/>
      <xs:element name="description" type="xs:string" minOccurs="0"/>
    </xs:sequence>
    <xs:attribute name="name" type="xs:string"/>
  </xs:complexType>


  <xs:complexType name="growingTips">
    <xs:sequence>
      <xs:element name="temperature" type="xs:int"/>
      <xs:element name="watering" type="xs:int"/>
    </xs:sequence>
    <xs:attribute name="value" type="lightingType"/>
  </xs:complexType>

  <xs:complexType name="VisualParameters">
    <xs:sequence>
      <xs:element name="stemColor" type="xs:string" minOccurs="0"/>
      <xs:element name="leafColor" type="xs:string" minOccurs="0"/>
      <xs:element name="averageSize" type="xs:int"/>
    </xs:sequence>
  </xs:complexType>

  <xs:simpleType name="multiplyingType">
    <xs:restriction base="SoilName"/>
  </xs:simpleType>

  <xs:complexType name="SoilType">
    <xs:sequence>
      <xs:element name="value" type="Soil" minOccurs="0"/>
    </xs:sequence>
  </xs:complexType>

  <xs:simpleType name="lightingType">
    <xs:restriction base="xs:string">
      <xs:enumeration value="photophilous"/>
      <xs:enumeration value="unphotophilous"/>
    </xs:restriction>
  </xs:simpleType>

  <xs:simpleType name="SoilName">
    <xs:restriction base="xs:string">
      <xs:enumeration value="byLeafs"/>
      <xs:enumeration value="byCutting"/>
      <xs:enumeration value="bySeeds"/>
    </xs:restriction>
  </xs:simpleType>

  <xs:simpleType name="Soil">
    <xs:restriction base="xs:string">
      <xs:enumeration value="podzolic"/>
      <xs:enumeration value="dirt"/>
      <xs:enumeration value="sodPodzolic"/>
    </xs:restriction>
  </xs:simpleType>
</xs:schema>

如何设置架构以成功验证xml？

Answer 1

我怀疑flowers元素定义是原因，它可能应该是：

<xs:complexType name="flowers">
   <xs:sequence>
     <xs:element name="flower" type="flower" maxOccurs="unbounded" />
   </xs:sequence>
 </xs:complexType>

Src-resolve：无法解析名字＆＃39;鲜花＆＃39;到A（n）＆＃39;类型定义＆＃39;零件

1 个答案: