Question

我提到了this LINK但是当我尝试使用相同的格式时，我很困惑我是否必须使用重复查询。但是我的查询过于冗长。请帮助我。

我的查询给出了以下结果：

is_active,    paid,  tags_title 
1             20    Testing
1             20    Development
1             21    Development
1             21    Testing
1             22    UI

必填结果：

is_active,    paid,  tags_title 
1             20    Testing, Development
1             21    Testing, Development
1             22    UI

更新下面的确切查询：

SELECT DISTINCT proj.is_active, tttm.tags_id,
       pal.project_artifact_id
       , STUFF((
            SELECT ',' + t.tags_title
            FROM task_tracker_tags T
            WHERE T.tags_id = tttm.tags_id
            FOR XML PATH('')
            ), 1, 1, '') AS tags_title

  FROM project_artifact_list pal 
LEFT JOIN task_tracker_mapper ttm 
ON ttm.artifact_id = pal.Project_Artifact_Id 
LEFT JOIN employees emp 
ON emp.employee_id = ttm.employee_id 
LEFT JOIN task_tracker_tags_mapper tttm  
ON tttm.artifact_id = pal.Project_Artifact_id 
LEFT JOIN projects proj
ON  proj.project_id = tttm.project_id 
WHERE  pal.Child_Priority IN ('High','Low')
AND pal.artifact_status IN ('Open')
AND emp.employee_id  IN (3932,1733)
AND proj.is_active = 1
AND pal.Due_Date <= '01/02/2017' 
AND pal.Due_Date >= '01/01/1800' 
GROUP BY proj.is_active,Project_Artifact_Id,tttm.tags_id;

Answer 1

我认为这是归档目标的最佳方式。

SELECT is_active, paid,
tags_title = STUFF(
             (SELECT ',' + tags_title FROM table FOR XML PATH ('')), 1, 1, ''
           ) 
FROM table GROUP BY is_active, paid

Answer 2

通过添加STUFF字段，您可以避免使用：

LEFT JOIN task_tracker_tags ttt 
    ON ttt.tags_id = tttm.tags_id


SELECT proj.is_active, 
       pal.paid, 

       title = STUFF(
                 (SELECT ',' + ttt.tags_title 
                  FROM task_tracker_tags ttt
                  WHERE ttt.tags_id = tttm.tags_id
                  FOR XML PATH ('')), 1, 1, '') 

FROM   person_aim_list pal 
       LEFT JOIN time_tace_map ttm 
              ON ttm.artifact_id = pal.paid 
       LEFT JOIN empires emp 
              ON emp.empire_id = ttm.empire_id 
       LEFT JOIN task_tracker_tags_mapper tttm 
              ON tttm.artifact_id = pal.paid 
       LEFT JOIN projects proj 
              ON proj.project_id = tttm.project_id 
WHERE  pal.child_priority IN ( 'High', 'Low' ) 
       AND pal.artifact_status IN ( 'Open' ) 
       AND emp.empire_id IN ( 3932, 1733 ) 
       AND proj.is_active = 1 
       AND pal.due_date <= '01/02/2017' 
       AND pal.due_date >= '01/01/1800'
GROUP BY proj.is_active, 
         pal.paid;

Answer 3

你可以这样做

SELECT DISTINCT proj.is_active, 
       pal.paid
       , STUFF((
            SELECT ',' + ttt.tags_title
            FROM task_tracker_tags T
            WHERE T.tags_id = tttm.tags_id
            FOR XML PATH('')
            ), 1, 1, '') AS tags_title

FROM   person_aim_list pal 
       LEFT JOIN time_tace_map ttm 
              ON ttm.artifact_id = pal.paid 
       LEFT JOIN empires emp 
              ON emp.empire_id = ttm.empire_id 
       LEFT JOIN task_tracker_tags_mapper tttm 
              ON tttm.artifact_id = pal.paid 
       /* removed
       LEFT JOIN task_tracker_tags ttt 
              ON ttt.tags_id = tttm.tags_id 
       */
       LEFT JOIN projects proj 
              ON proj.project_id = tttm.project_id 
WHERE  pal.child_priority IN ( 'High', 'Low' ) 
       AND pal.artifact_status IN ( 'Open' ) 
       AND emp.empire_id IN ( 3932, 1733 ) 
       AND proj.is_active = 1 
       AND pal.due_date <= '01/02/2017' 
       AND pal.due_date >= '01/01/1800'

修改

在您的更新中，您提到了4列，例如

SELECT DISTINCT proj.is_active, tttm.tags_id, pal.project_artifact_id , STUFF(( SELECT ',' + t.tags_title FROM task_tracker_tags T WHERE T.tags_id = tttm.tags_id FOR XML PATH('') ), 1, 1, '') AS tags_title

您需要将其更改为

SELECT DISTINCT proj.is_active ---, tttm.tags_id, Here your query making wrong output. ,pal.project_artifact_id , STUFF(( SELECT ',' + t.tags_title FROM task_tracker_tags T WHERE T.tags_id = tttm.tags_id FOR XML PATH('') ), 1, 1, '') AS tags_title

Group By和STUFF组合在sql server中

3 个答案: