Question

我需要行编号，其中ROW_NUMBER对于相同的值列是相同的：MFGPN（相同的MFGPN将始终按顺序）。我还需要保留原始序列号

这是我的表

No     MFGPN
1      Z363700Z01
2      Z363700Z01
3      0119-960-1
4      1A3F1-0503-01

我尝试使用RANK（）来实现所需，但遇到了麻烦。

SELECT RANK() OVER(ORDER BY MFGPN) As [Item], MFGPN FROM Table1 ORDER BY [No] ASC

RESULT

Item   MFGPN           Desired Result
3      Z363700Z01            1
3      Z363700Z01            1
1      0119-960-1            2
2      1A3F1-0503-01         3

感谢你们＆＃39;专家建议。谢谢！

Answer 1

使用DENSE_RANK窗口函数代替RANK。当数据重复Rank时，Dense_Rank将跳过序列。

SELECT MFGPN,
        Dense_rank()OVER(ORDER BY m_no) as [Desired Result]
FROM   (SELECT no,
                MFGPN,
                Min(no)OVER(partition BY MFGPN) AS m_no
        FROM   (VALUES (1,'Z363700Z01' ),
                        (2,'Z363700Z01' ),
                        (3,'0119-960-1' ),
                        (4,'1A3F1-0503-01')) tc (no, MFGPN))a

如果no不唯一，请将DENSE_RANK更改为

Dense_rank()OVER(ORDER BY m_no,MFGPN)

结果：

+---------------+----------------+
|     MFGPN     | Desired Result |
+---------------+----------------+
| Z363700Z01    |              1 |
| Z363700Z01    |              1 |
| 0119-960-1    |              2 |
| 1A3F1-0503-01 |              3 |
+---------------+----------------+

Answer 2

您应该按mfgpn对结果进行分区，以便具有相同mfgpn的行按no获得相同的排名和顺序。此外，使用dense_rank可确保您不会跳过＆＃34;任何级别：

SELECT   DENSE_RANK() OVER(PARTITION BY [mfgpn] ORDER BY [no]) As [Item], 
         [mfgpm] 
FROM     Table1 
ORDER BY [No] ASC

Answer 3

select      sum(case when MFGPN = prev_MFGPN then 0 else 1 end) over (order by No)  as item
           ,MFGPN

from       (SELECT      lag(MFGPN) over (order by [No]) as prev_MFGPN   
                       ,[No]
                       ,MFGPN 
            FROM        Table1 
            ) t

ORDER BY    [No] ASC

+------+---------------+
| item | MFGPN         |
+------+---------------+
| 1    | Z363700Z01    |
+------+---------------+
| 1    | Z363700Z01    |
+------+---------------+
| 2    | 0119-960-1    |
+------+---------------+
| 3    | 1A3F1-0503-01 |
+------+---------------+

Answer 4

您可以尝试下面的代码段。 DENSE_RANK（）在上面解释了这种情况下的最佳方法。

    SELECT a.*,
      DENSE_RANK() OVER(ORDER BY MFGPN DESC) RN
    FROM
      (SELECT 1 AS no, 'Z363700Z01' AS mfgpn FROM dual
      UNION ALL
      SELECT 2 AS no, 'Z363700Z01' AS mfgpn FROM dual
      UNION ALL
      SELECT 3 AS no, '0119-960-1' AS mfgpn FROM dual
      UNION ALL
      SELECT 4 AS no, '1A3F1-0503-01' AS MFGPN FROM dual
      )a;

-------------------------------OUTPUT-------------------------------------------
NO  MFGPN           RN
1   Z363700Z01      1
2   Z363700Z01      1
4   1A3F1-0503-01   2
3   0119-960-1      3

--------------------------------------------------------------------------------

Answer 5

尝试：我认为使用join并比较值以获得所需的输出更加简单灵活，如下所示：

SELECT p.MFGPN,
       Dense_rank()OVER(ORDER BY CASE WHEN p.MFGPN = tp.MFGPN THEN tp.num ELSE p.num END) AS [Desired Result]
FROM tmp_option p
LEFT JOIN tmp_option tp ON tp.num+1 = p.num
ORDER BY p.num ASC

相同值的相同Row_Number

5 个答案: