Question

以下查询在第一个分区集之后导致重复的row_numbers。例如，第一组fldPK = 2403和fldCIA = 1我收到以下内容......

2403    1    1
2403    1    2
2403    1    3
2403    1    4

在第二集中我收到......

2403    2    1
2403    2    1 <-- duplicate 1 within the same partition
2403    2    2
2403    2    3

    SELECT *, 1 AS fldBF, 
              ROW_NUMBER() OVER (PARTITION BY fldPK, fldCIA ORDER BY fldPK) AS sCount 
    INTO #tmpTable 
    FROM V_qryCSPGA 
    WHERE fldPK IN(SELECT DISTINCT thePK FROM FN_qryAllDTPK()) 

    UNION ALL   

    SELECT *, 1 AS fldBF, 
              ROW_NUMBER() OVER (PARTITION BY fldPK, fldCIA ORDER BY fldPK) AS sCount 
    FROM FN_qryCSGBA() 
    WHERE fldPK IN(SELECT DISTINCT thePK FROM FN_qryAllDTPK())
    ORDER BY fldPK, fldCIA, fldNDat;

为什么会这样？对于fldPK和fldCIA的每一组，我需要一个重新开始行号的计数为1，更合适的数据将是......

2403    3    1
2403    3    2
2403    3    3
2403    3    4
2403    3    5
2403    3    6
2403    3    7
2403    3    8
2403    3    9

Answer 1

这将停止重复的数字。新的编号是否与你真正想要的完全相同，是另一回事：

; WITH cte AS
  ( SELECT *, 1 AS fldBF
    FROM V_qryCSPGA 
    WHERE fldPK IN(SELECT DISTINCT thePK FROM FN_qryAllDTPK()) 

    UNION ALL   

    SELECT *, 1 AS fldBF
    FROM FN_qryCSGBA() 
    WHERE fldPK IN(SELECT DISTINCT thePK FROM FN_qryAllDTPK())
  )
SELECT *, 
       ROW_NUMBER() OVER (PARTITION BY fldPK, fldCIA ORDER BY fldPK) AS sCount 
INTO #tmpTable 
FROM cte 
ORDER BY fldPK, fldCIA, fldNDat;

ROW_NUMBER（）OVER PARTITION返回重复值

1 个答案: