Question

我知道这个问题很多次，但仍然困惑，无法找到解决方案。

我有一个MainWindow和一个类。

在我班上，我有一个信号，我在方法调用中发出。

问题：Slot方法没有触发。

这是我的代码。

BWorker.h

#pragma once

#include <QObject>

class BWorker : public QObject
{
    Q_OBJECT

public:
    BWorker(QObject *parent);
    ~BWorker();
    void doSomething();

signals:
    void signalSomething();

};

BWorker.cpp

#include "BWorker.h"

BWorker::BWorker(QObject *parent)
    : QObject(parent)
{
}

BWorker::~BWorker()
{
}

void BWorker::doSomething() 
{
    emit signalSomething();
}

QtGuiApplication1.h

#pragma once

#include <QtWidgets/QMainWindow>
#include "ui_QtGuiApplication1.h"

class QtGuiApplication1 : public QMainWindow
{
    Q_OBJECT

public:
    QtGuiApplication1(QWidget *parent = Q_NULLPTR);

public slots:
    void workDone();

private:
    Ui::QtGuiApplication1Class ui;
};

QtGuiApplication1.cpp

#include "QtGuiApplication1.h"
#include "BWorker.h"

QtGuiApplication1::QtGuiApplication1(QWidget *parent)
    : QMainWindow(parent)
{
    ui.setupUi(this);

    BWorker bworker(this);

    connect(&bworker, SIGNAL(bworker.signalSomething), this, SLOT(workDone()));

    bworker.doSomething();

}

void QtGuiApplication1::workDone() {

}

Answer 1

你的问题在这里：

SIGNAL(bworker.signalSomething)

这是无效的，你应该在终端看到一条消息说没有这样的信号。您案例的正确语法是：

SIGNAL(signalSomething())

Answer 2

请通过复制粘贴发布您的代码。不要编辑代码：问题可能出现在您编辑的的。

我的代码工作正常。

mainwindow.h：

#ifndef MAINWINDOW_H #define MAINWINDOW_H #include <QMainWindow> namespace Ui { class MainWindow; } class MainWindow : public QMainWindow { Q_OBJECT public: explicit MainWindow(QWidget *parent = 0); ~MainWindow(); public slots: void workDone(); private: Ui::MainWindow *ui; }; #endif // MAINWINDOW_H

mainwindow.cpp：

#include "mainwindow.h" #include "ui_mainwindow.h" #include <QDebug> #include "worker.h" MainWindow::MainWindow(QWidget *parent) : QMainWindow(parent), ui(new Ui::MainWindow) { ui->setupUi(this); Worker worker(this); connect(&worker, SIGNAL(signalSomething()), this, SLOT(workDone())); //connect(&worker, &Worker::signalSomething, this, &MainWindow::workDone); worker.doSomething(); } MainWindow::~MainWindow() { delete ui; } void MainWindow::workDone() { qDebug() << "Done."; }

worker.h：

#ifndef WORKER_H #define WORKER_H #include <QObject> class Worker : public QObject { Q_OBJECT public: explicit Worker(QObject *parent = 0); void doSomething(); signals: void signalSomething(); public slots: }; #endif // WORKER_H

worker.cpp：

#include "worker.h" Worker::Worker(QObject *parent) : QObject(parent) { } void Worker::doSomething() { emit signalSomething(); }

申请表输出：

Debugging starts Done. Debugging has finished

打印出来＆＃34;完成。＆＃34;意味着代码正在运作。

Qt插槽方法（这是另一个类）在发出信号时不触发

2 个答案: