Question

我有一系列像这样的对象;

var orders = [
  {
    status: "pending"
  },
  {
    status: "received"
  },
  {
    status: "sent"
  },
  {
    status: "pending"
  }
]

我想根据status键的值对这个对象数组进行排序，但是这样对象的顺序与status键的可能值的数组顺序相匹配;

var statuses = ["pending", "sent", "received"]

因此，排序后，首先是两个"pending"对象，然后是"sent"对象，最后是"received"对象。

我该怎么做？

Answer 1

您可以使用sort()和indexOf()执行此操作。

＆＃13;

var orders = [{
  status: "pending"
}, {
  status: "received"
}, {
  status: "sent"
}, {
  status: "pending"
}]
var statuses = ["pending", "sent", "received"]

var result = orders.sort(function(a, b) {
  return statuses.indexOf(a.status) - statuses.indexOf(b.status)
})

console.log(result)

＆＃13;

Answer 2

您可以使用sort()功能：

＆＃13;

var statuses = ["pending", "sent", "received"];
var orders = [
  {
    status: "pending"
  },
  {
    status: "received"
  },
  {
    status: "sent"
  },
  {
    status: "pending"
  }
];

orders.sort(function(a, b) {
  return statuses.indexOf(a.status) - statuses.indexOf(b.status); 
});

console.log(orders);

＆＃13;

Answer 3

使用Array#sort方法对对象数组进行排序。使用对象存储键的索引有助于避免使用Array#indexOf方法（速度较慢）。

var orders = [{
  status: "pending"
}, {
  status: "received"
}, {
  status: "sent"
}, {
  status: "pending"
}];

var statuses = ["pending", "sent", "received"];

// generate the object which holds the index in array
// or use an object instead of array which holds the index
var index = statuses.reduce(function(obj, k, i) {
  obj[k] = i;
  return obj;
}, {})

console.log(
  orders.sort(function(a, b) {
    return index[a.status] - index[b.status];
  })
)

Answer 4

您可以将对象用作排序顺序的哈希表。

＆＃13;

var orders = [{ status: "pending" }, { status: "received" }, { status: "sent" }, { status: "pending" }],
    statuses = { pending: 1, sent: 2, received: 3 };

orders.sort(function (a, b) {
    return statuses[a.status] - statuses[b.status];
});

console.log(orders);

＆＃13;

Answer 5

可以在排序回调中使用indexOf()之类的方法，但更有效的方法是首先构建索引的hashmap

var statIndex = statuses.reduce(function(a,c,i){
   a[c] = i;
   return a
},{})

orders.sort(function(a,b){
   return statIndex[a.status] - statIndex[b.status]
})

按数组对对象数组进行排序

5 个答案: