我使用Ajax读取以下对象并将它们存储在一个数组中：
var homes = [
{
"h_id": "3",
"city": "Dallas",
"state": "TX",
"zip": "75201",
"price": "162500"
}, {
"h_id": "4",
"city": "Bevery Hills",
"state": "CA",
"zip": "90210",
"price": "319250"
}, {
"h_id": "5",
"city": "New York",
"state": "NY",
"zip": "00010",
"price": "962500"
}
];
如何使用JavaScript创建一个函数，以按升序 或 降序顺序中的price属性对对象进行排序？
答案 0 :(得分：1469)
按价格按升序排序房屋：
homes.sort(function(a, b) {
return parseFloat(a.price) - parseFloat(b.price);
});
或者在ES6版本之后：
homes.sort((a, b) => parseFloat(a.price) - parseFloat(b.price));
可以找到一些文档here。
答案 1 :(得分：643)
这是一个更灵活的版本，允许您创建 可重复使用的排序功能，并按任何字段排序。
var sort_by = function(field, reverse, primer){
var key = primer ?
function(x) {return primer(x[field])} :
function(x) {return x[field]};
reverse = !reverse ? 1 : -1;
return function (a, b) {
return a = key(a), b = key(b), reverse * ((a > b) - (b > a));
}
}
现在您可以随意按任意字段排序......
var homes = [{
"h_id": "3",
"city": "Dallas",
"state": "TX",
"zip": "75201",
"price": "162500"
}, {
"h_id": "4",
"city": "Bevery Hills",
"state": "CA",
"zip": "90210",
"price": "319250"
}, {
"h_id": "5",
"city": "New York",
"state": "NY",
"zip": "00010",
"price": "962500"
}];
// Sort by price high to low
homes.sort(sort_by('price', true, parseInt));
// Sort by city, case-insensitive, A-Z
homes.sort(sort_by('city', false, function(a){return a.toUpperCase()}));
答案 2 :(得分：129)
要对它进行排序，您需要创建一个带有两个参数的比较器函数。然后使用该比较器函数调用sort函数，如下所示：
// a and b are object elements of your array
function mycomparator(a,b) {
return parseInt(a.price, 10) - parseInt(b.price, 10);
}
homes.sort(mycomparator);
如果要对升序进行排序，请在减号的每一侧切换表达式。
答案 3 :(得分：44)
用于字符串排序，以防有人需要它，
var dataArr = {
"hello": [{
"id": 114,
"keyword": "zzzzzz",
"region": "Sri Lanka",
"supportGroup": "administrators",
"category": "Category2"
}, {
"id": 115,
"keyword": "aaaaa",
"region": "Japan",
"supportGroup": "developers",
"category": "Category2"
}]
};
var sortArray = dataArr['hello'];
sortArray.sort(function(a,b) {
if ( a.region < b.region )
return -1;
if ( a.region > b.region )
return 1;
return 0;
} );
答案 4 :(得分：31)
如果您有ES6兼容的浏览器，则可以使用：
升序和降序排序顺序之间的差异是比较函数返回的值的符号：
var ascending = homes.sort((a, b) => Number(a.price) - Number(b.price));
var descending = homes.sort((a, b) => Number(b.price) - Number(a.price));
这是一个有效的代码片段：
var homes = [{
"h_id": "3",
"city": "Dallas",
"state": "TX",
"zip": "75201",
"price": "162500"
}, {
"h_id": "4",
"city": "Bevery Hills",
"state": "CA",
"zip": "90210",
"price": "319250"
}, {
"h_id": "5",
"city": "New York",
"state": "NY",
"zip": "00010",
"price": "962500"
}];
homes.sort((a, b) => Number(a.price) - Number(b.price));
console.log("ascending", homes);
homes.sort((a, b) => Number(b.price) - Number(a.price));
console.log("descending", homes);
答案 5 :(得分：22)
你想用Javascript对它进行排序，对吗？你想要的是sort() function。在这种情况下，您需要编写一个比较器函数并将其传递给sort()，如下所示：
function comparator(a, b) {
return parseInt(a["price"], 10) - parseInt(b["price"], 10);
}
var json = { "homes": [ /* your previous data */ ] };
console.log(json["homes"].sort(comparator));
你的比较器采用数组中每个嵌套哈希中的一个，并通过检查“price”字段来决定哪一个更高。
答案 6 :(得分：20)
我建议GitHub: Array sortBy - 使用Schwartzian transform
的sortBy方法的最佳实现
但是现在我们将尝试这种方法Gist: sortBy-old.js 让我们创建一个方法来排序能够通过某些属性排列对象的数组。
var sortBy = (function () {
var toString = Object.prototype.toString,
// default parser function
parse = function (x) { return x; },
// gets the item to be sorted
getItem = function (x) {
var isObject = x != null && typeof x === "object";
var isProp = isObject && this.prop in x;
return this.parser(isProp ? x[this.prop] : x);
};
/**
* Sorts an array of elements.
*
* @param {Array} array: the collection to sort
* @param {Object} cfg: the configuration options
* @property {String} cfg.prop: property name (if it is an Array of objects)
* @property {Boolean} cfg.desc: determines whether the sort is descending
* @property {Function} cfg.parser: function to parse the items to expected type
* @return {Array}
*/
return function sortby (array, cfg) {
if (!(array instanceof Array && array.length)) return [];
if (toString.call(cfg) !== "[object Object]") cfg = {};
if (typeof cfg.parser !== "function") cfg.parser = parse;
cfg.desc = !!cfg.desc ? -1 : 1;
return array.sort(function (a, b) {
a = getItem.call(cfg, a);
b = getItem.call(cfg, b);
return cfg.desc * (a < b ? -1 : +(a > b));
});
};
}());
var data = [
{date: "2011-11-14T16:30:43Z", quantity: 2, total: 90, tip: 0, type: "tab"},
{date: "2011-11-14T17:22:59Z", quantity: 2, total: 90, tip: 0, type: "Tab"},
{date: "2011-11-14T16:28:54Z", quantity: 1, total: 300, tip: 200, type: "visa"},
{date: "2011-11-14T16:53:41Z", quantity: 2, total: 90, tip: 0, type: "tab"},
{date: "2011-11-14T16:48:46Z", quantity: 2, total: 90, tip: 0, type: "tab"},
{date: "2011-11-14T17:25:45Z", quantity: 2, total: 200, tip: 0, type: "cash"},
{date: "2011-11-31T17:29:52Z", quantity: 1, total: 200, tip: 100, type: "Visa"},
{date: "2011-11-14T16:58:03Z", quantity: 2, total: 90, tip: 0, type: "tab"},
{date: "2011-11-14T16:20:19Z", quantity: 2, total: 190, tip: 100, type: "tab"},
{date: "2011-11-01T16:17:54Z", quantity: 2, total: 190, tip: 100, type: "tab"},
{date: "2011-11-14T17:07:21Z", quantity: 2, total: 90, tip: 0, type: "tab"},
{date: "2011-11-14T16:54:06Z", quantity: 1, total: 100, tip: 0, type: "Cash"}
];
按"date" String
// sort by @date (ascending)
sortBy(data, { prop: "date" });
// expected: first element
// { date: "2011-11-01T16:17:54Z", quantity: 2, total: 190, tip: 100, type: "tab" }
// expected: last element
// { date: "2011-11-31T17:29:52Z", quantity: 1, total: 200, tip: 100, type: "Visa"}
如果您想忽略区分大小写，请设置parser回调：
// sort by @type (ascending) IGNORING case-sensitive
sortBy(data, {
prop: "type",
parser: (t) => t.toUpperCase()
});
// expected: first element
// { date: "2011-11-14T16:54:06Z", quantity: 1, total: 100, tip: 0, type: "Cash" }
// expected: last element
// { date: "2011-11-31T17:29:52Z", quantity: 1, total: 200, tip: 100, type: "Visa" }
如果您想将"date"字段转换为Date类型：
// sort by @date (descending) AS Date object
sortBy(data, {
prop: "date",
desc: true,
parser: (d) => new Date(d)
});
// expected: first element
// { date: "2011-11-31T17:29:52Z", quantity: 1, total: 200, tip: 100, type: "Visa"}
// expected: last element
// { date: "2011-11-01T16:17:54Z", quantity: 2, total: 190, tip: 100, type: "tab" }
在这里你可以玩代码： jsbin.com/lesebi
感谢 @Ozesh 的反馈意见，修复了与 falsy 值相关的问题。
答案 7 :(得分：16)
使用lodash.sortBy，（使用commonjs的说明，您也可以将script include-tag for the cdn放在HTML的顶部）
var sortBy = require('lodash.sortby');
// or
sortBy = require('lodash').sortBy;
降序
var descendingOrder = sortBy( homes, 'price' ).reverse();
升序
var ascendingOrder = sortBy( homes, 'price' );
答案 8 :(得分：7)
这可以通过简单的一行 valueof（）排序功能来实现。请在下方运行代码段以查看演示。
var homes = [
{
"h_id": "3",
"city": "Dallas",
"state": "TX",
"zip": "75201",
"price": "162500"
}, {
"h_id": "4",
"city": "Bevery Hills",
"state": "CA",
"zip": "90210",
"price": "319250"
}, {
"h_id": "5",
"city": "New York",
"state": "NY",
"zip": "00010",
"price": "962500"
}
];
console.log("To sort descending/highest first, use operator '<'");
homes.sort(function(a,b) { return a.price.valueOf() < b.price.valueOf();});
console.log(homes);
console.log("To sort ascending/lowest first, use operator '>'");
homes.sort(function(a,b) { return a.price.valueOf() > b.price.valueOf();});
console.log(homes);
答案 9 :(得分：5)
我参加聚会的时间不多，但下面是我排序的逻辑。
function getSortedData(data, prop, isAsc){
return data.sort((a, b)=>{
return (a[prop] < b[prob] ? -1: 1 ) * (isAsc ? 1 : -1)
});
}
答案 10 :(得分：3)
以上是上述所有答案的高潮。
小提琴验证：http://jsfiddle.net/bobberino/4qqk3/
var sortOn = function (arr, prop, reverse, numeric) {
// Ensure there's a property
if (!prop || !arr) {
return arr
}
// Set up sort function
var sort_by = function (field, rev, primer) {
// Return the required a,b function
return function (a, b) {
// Reset a, b to the field
a = primer(a[field]), b = primer(b[field]);
// Do actual sorting, reverse as needed
return ((a < b) ? -1 : ((a > b) ? 1 : 0)) * (rev ? -1 : 1);
}
}
// Distinguish between numeric and string to prevent 100's from coming before smaller
// e.g.
// 1
// 20
// 3
// 4000
// 50
if (numeric) {
// Do sort "in place" with sort_by function
arr.sort(sort_by(prop, reverse, function (a) {
// - Force value to a string.
// - Replace any non numeric characters.
// - Parse as float to allow 0.02 values.
return parseFloat(String(a).replace(/[^0-9.-]+/g, ''));
}));
} else {
// Do sort "in place" with sort_by function
arr.sort(sort_by(prop, reverse, function (a) {
// - Force value to string.
return String(a).toUpperCase();
}));
}
}
答案 11 :(得分：3)
如果您使用Underscore.js，请尝试sortBy：
// price is of an integer type
_.sortBy(homes, "price");
// price is of a string type
_.sortBy(homes, function(home) {return parseInt(home.price);});
答案 12 :(得分：3)
您可以使用string1.localeCompare（string2）进行字符串比较
this.myArray.sort((a,b) => {
return a.stringProp.localeCompare(b.stringProp);
});
请注意，localCompare区分大小写，
答案 13 :(得分：3)
您可以将JavaScript sort方法与回调函数一起使用：
function compareASC(homeA, homeB)
{
return parseFloat(homeA.price) - parseFloat(homeB.price);
}
function compareDESC(homeA, homeB)
{
return parseFloat(homeB.price) - parseFloat(homeA.price);
}
// Sort ASC
homes.sort(compareASC);
// Sort DESC
homes.sort(compareDESC);
答案 14 :(得分：3)
我还使用某种评级和多个字段排序：
arr = [
{type:'C', note:834},
{type:'D', note:732},
{type:'D', note:008},
{type:'F', note:474},
{type:'P', note:283},
{type:'P', note:165},
{type:'X', note:173},
{type:'Z', note:239},
];
arr.sort(function(a,b){
var _a = ((a.type==='C')?'0':(a.type==='P')?'1':'2');
_a += (a.type.localeCompare(b.type)===-1)?'0':'1';
_a += (a.note>b.note)?'1':'0';
var _b = ((b.type==='C')?'0':(b.type==='P')?'1':'2');
_b += (b.type.localeCompare(a.type)===-1)?'0':'1';
_b += (b.note>a.note)?'1':'0';
return parseInt(_a) - parseInt(_b);
});
结果
[
{"type":"C","note":834},
{"type":"P","note":165},
{"type":"P","note":283},
{"type":"D","note":8},
{"type":"D","note":732},
{"type":"F","note":474},
{"type":"X","note":173},
{"type":"Z","note":239}
]
答案 15 :(得分：2)
虽然仅对单个数组进行排序有点过分，但这个原型函数允许使用{{升序或降序，包括嵌套键按任意键对Javascript数组进行排序。 1}}语法。
dot用法：
(function(){
var keyPaths = [];
var saveKeyPath = function(path) {
keyPaths.push({
sign: (path[0] === '+' || path[0] === '-')? parseInt(path.shift()+1) : 1,
path: path
});
};
var valueOf = function(object, path) {
var ptr = object;
for (var i=0,l=path.length; i<l; i++) ptr = ptr[path[i]];
return ptr;
};
var comparer = function(a, b) {
for (var i = 0, l = keyPaths.length; i < l; i++) {
aVal = valueOf(a, keyPaths[i].path);
bVal = valueOf(b, keyPaths[i].path);
if (aVal > bVal) return keyPaths[i].sign;
if (aVal < bVal) return -keyPaths[i].sign;
}
return 0;
};
Array.prototype.sortBy = function() {
keyPaths = [];
for (var i=0,l=arguments.length; i<l; i++) {
switch (typeof(arguments[i])) {
case "object": saveKeyPath(arguments[i]); break;
case "string": saveKeyPath(arguments[i].match(/[+-]|[^.]+/g)); break;
}
}
return this.sort(comparer);
};
})();
使用点语法或数组语法按嵌套属性排序：
var data = [
{ name: { first: 'Josh', last: 'Jones' }, age: 30 },
{ name: { first: 'Carlos', last: 'Jacques' }, age: 19 },
{ name: { first: 'Carlos', last: 'Dante' }, age: 23 },
{ name: { first: 'Tim', last: 'Marley' }, age: 9 },
{ name: { first: 'Courtney', last: 'Smith' }, age: 27 },
{ name: { first: 'Bob', last: 'Smith' }, age: 30 }
]
data.sortBy('age'); // "Tim Marley(9)", "Carlos Jacques(19)", "Carlos Dante(23)", "Courtney Smith(27)", "Josh Jones(30)", "Bob Smith(30)"
按多个键排序：
data.sortBy('name.first'); // "Bob Smith(30)", "Carlos Dante(23)", "Carlos Jacques(19)", "Courtney Smith(27)", "Josh Jones(30)", "Tim Marley(9)"
data.sortBy(['name', 'first']); // "Bob Smith(30)", "Carlos Dante(23)", "Carlos Jacques(19)", "Courtney Smith(27)", "Josh Jones(30)", "Tim Marley(9)"
答案 16 :(得分：2)
使用ECMAScript 6 StoBor的答案可以更简洁：
homes.sort((a, b) => a.price - b.price)
答案 17 :(得分：2)
仅适用于常规元素值数组：
function sortArrayOfElements(arrayToSort) {
function compareElements(a, b) {
if (a < b)
return -1;
if (a > b)
return 1;
return 0;
}
return arrayToSort.sort(compareElements);
}
e.g. 1:
var array1 = [1,2,545,676,64,2,24]
output : [1, 2, 2, 24, 64, 545, 676]
var array2 = ["v","a",545,676,64,2,"24"]
output: ["a", "v", 2, "24", 64, 545, 676]
对于一个对象数组：
function sortArrayOfObjects(arrayToSort, key) {
function compareObjects(a, b) {
if (a[key] < b[key])
return -1;
if (a[key] > b[key])
return 1;
return 0;
}
return arrayToSort.sort(compareObjects);
}
e.g. 1: var array1= [{"name": "User4", "value": 4},{"name": "User3", "value": 3},{"name": "User2", "value": 2}]
output : [{"name": "User2", "value": 2},{"name": "User3", "value": 3},{"name": "User4", "value": 4}]
答案 18 :(得分：1)
价格降序：
homes.sort((x,y) => {return y.price - x.price})
价格升序：
homes.sort((x,y) => {return x.price - y.price})
答案 19 :(得分：1)
虽然我知道OP希望对一组数字进行排序，但这个问题已被标记为关于字符串的类似问题的答案。为此，上述答案不考虑对外壳重要的文本数组进行排序。大多数答案采用字符串值并将它们转换为大写/小写，然后按这种或那种方式排序。我坚持的要求很简单：
我期望的是[ A, a, B, b, C, c ]，但上面的答案会返回A, B, C, a, b, c。我实际上对此感到头疼的时间超过了我想要的时间（这就是为什么我发布这个，希望它能帮助至少一个其他人）。虽然两个用户在标记答案的注释中提到localeCompare函数，但直到我在搜索时偶然发现函数之后才看到它。在阅读the String.prototype.localeCompare() documentation之后，我能够想出这个：
var values = [ "Delta", "charlie", "delta", "Charlie", "Bravo", "alpha", "Alpha", "bravo" ];
var sorted = values.sort((a, b) => a.localeCompare(b, undefined, { caseFirst: "upper" }));
// Result: [ "Alpha", "alpha", "Bravo", "bravo", "Charlie", "charlie", "Delta", "delta" ]
这告诉函数在小写值之前对大写值进行排序。 localeCompare函数中的第二个参数是定义区域设置，但如果将其保留为undefined，它会自动为您确定区域设置。
这对于排序对象数组也是一样的：
var values = [
{ id: 6, title: "Delta" },
{ id: 2, title: "charlie" },
{ id: 3, title: "delta" },
{ id: 1, title: "Charlie" },
{ id: 8, title: "Bravo" },
{ id: 5, title: "alpha" },
{ id: 4, title: "Alpha" },
{ id: 7, title: "bravo" }
];
var sorted = values
.sort((a, b) => a.title.localeCompare(b.title, undefined, { caseFirst: "upper" }));
答案 20 :(得分：1)
您需要两个功能
function desc(a, b) {
return b < a ? -1 : b > a ? 1 : b >= a ? 0 : NaN;
}
function asc(a, b) {
return a < b ? -1 : a > b ? 1 : a >= b ? 0 : NaN;
}
然后您可以将其应用于任何对象属性：
data.sort((a, b) => desc(parseFloat(a.price), parseFloat(b.price)));
let data = [
{label: "one", value:10},
{label: "two", value:5},
{label: "three", value:1},
];
// sort functions
function desc(a, b) {
return b < a ? -1 : b > a ? 1 : b >= a ? 0 : NaN;
}
function asc(a, b) {
return a < b ? -1 : a > b ? 1 : a >= b ? 0 : NaN;
}
// DESC
data.sort((a, b) => desc(a.value, b.value));
document.body.insertAdjacentHTML(
'beforeend',
'<strong>DESCending sorted</strong><pre>' + JSON.stringify(data) +'</pre>'
);
// ASC
data.sort((a, b) => asc(a.value, b.value));
document.body.insertAdjacentHTML(
'beforeend',
'<strong>ASCending sorted</strong><pre>' + JSON.stringify(data) +'</pre>'
);
答案 21 :(得分：1)
以下是“JavaScript：The Good Parts”一书中优雅实现的略微修改版本。
注意：此版本的by 稳定。它在执行下一个链式排序时保留第一种排序。
我已添加isAscending参数。还根据作者的建议将其转换为ES6标准和“更新”的好部分。
您可以按多个属性对升序以及降序和链排序进行排序。
const by = function (name, minor, isAscending=true) {
const reverseMutliplier = isAscending ? 1 : -1;
return function (o, p) {
let a, b;
let result;
if (o && p && typeof o === "object" && typeof p === "object") {
a = o[name];
b = p[name];
if (a === b) {
return typeof minor === 'function' ? minor(o, p) : 0;
}
if (typeof a === typeof b) {
result = a < b ? -1 : 1;
} else {
result = typeof a < typeof b ? -1 : 1;
}
return result * reverseMutliplier;
} else {
throw {
name: "Error",
message: "Expected an object when sorting by " + name
};
}
};
};
let s = [
{first: 'Joe', last: 'Besser'},
{first: 'Moe', last: 'Howard'},
{first: 'Joe', last: 'DeRita'},
{first: 'Shemp', last: 'Howard'},
{first: 'Larry', last: 'Fine'},
{first: 'Curly', last: 'Howard'}
];
// Sort by: first ascending, last ascending
s.sort(by("first", by("last")));
console.log("Sort by: first ascending, last ascending: ", s); // "[
// {"first":"Curly","last":"Howard"},
// {"first":"Joe","last":"Besser"}, <======
// {"first":"Joe","last":"DeRita"}, <======
// {"first":"Larry","last":"Fine"},
// {"first":"Moe","last":"Howard"},
// {"first":"Shemp","last":"Howard"}
// ]
// Sort by: first ascending, last descending
s.sort(by("first", by("last", 0, false)));
console.log("sort by: first ascending, last descending: ", s); // "[
// {"first":"Curly","last":"Howard"},
// {"first":"Joe","last":"DeRita"}, <========
// {"first":"Joe","last":"Besser"}, <========
// {"first":"Larry","last":"Fine"},
// {"first":"Moe","last":"Howard"},
// {"first":"Shemp","last":"Howard"}
// ]
答案 22 :(得分：1)
要对数组进行排序，必须定义比较器函数。此功能在您所需的排序模式或顺序（即升序或降序）上总是不同。
让我们创建一些函数，对数组进行升序或降序排序，并包含对象或字符串或数值。
function sorterAscending(a,b) {
return a-b;
}
function sorterDescending(a,b) {
return b-a;
}
function sorterPriceAsc(a,b) {
return parseInt(a['price']) - parseInt(b['price']);
}
function sorterPriceDes(a,b) {
return parseInt(b['price']) - parseInt(b['price']);
}
按数字排序（按字母顺序排列）：
var fruits = ["Banana", "Orange", "Apple", "Mango"];
fruits.sort();
对数字进行排序（按字母顺序排列和降序排列）：
var fruits = ["Banana", "Orange", "Apple", "Mango"];
fruits.sort();
fruits.reverse();
排序数字（数字和升序）：
var points = [40,100,1,5,25,10];
points.sort(sorterAscending());
对数字进行排序（数字和降序）：
var points = [40,100,1,5,25,10];
points.sort(sorterDescending());
如上所述，将sorterPriceAsc和sorterPriceDes方法与带有所需键的数组一起使用。
homes.sort(sorterPriceAsc()) or homes.sort(sorterPriceDes())
答案 23 :(得分：1)
更像 LINQ 的解决方案：
lst = [{
"content": "abc",
'entities': [
[44, 55, "SEN"],
[27, 31, "FIN"]
]
}, {
"content": "xyz",
'entities': [
[8, 17, "FIN"]
]
}, {
"content": "klm",
'entities': [
[18, 26, "FIN"]
]
}]
output = [( elt["content"], { "entities": [tuple(e) for e in elt["entities"]] } ) for elt in lst]
print(output)
优点：
用法：
Array.prototype.orderBy = function (selector, desc = false) {
return [...this].sort((a, b) => {
a = selector(a);
b = selector(b);
if (a == b) return 0;
return (desc ? a > b : a < b) ? -1 : 1;
});
}
答案 24 :(得分：0)
function compareValues(key, order = 'asc') {
return function innerSort(a, b) {
if (!a.hasOwnProperty(key) || !b.hasOwnProperty(key)) {
// property doesn't exist on either object
return 0;
}
const varA = (typeof a[key] === 'string')
? a[key].toUpperCase() : a[key];
const varB = (typeof b[key] === 'string')
? b[key].toUpperCase() : b[key];
let comparison = 0;
if (varA > varB) {
comparison = 1;
} else if (varA < varB) {
comparison = -1;
}
return (
(order === 'desc') ? (comparison * -1) : comparison
);
};
}
http://yazilimsozluk.com/sort-array-in-javascript-by-asc-or-desc
答案 25 :(得分：0)
一个简单的代码：
var homes = [
{
"h_id": "3",
"city": "Dallas",
"state": "TX",
"zip": "75201",
"price": "162500"
}, {
"h_id": "4",
"city": "Bevery Hills",
"state": "CA",
"zip": "90210",
"price": "319250"
}, {
"h_id": "5",
"city": "New York",
"state": "NY",
"zip": "00010",
"price": "962500"
}
];
let sortByPrice = homes.sort(function (a, b)
{
return parseFloat(b.price) - parseFloat(a.price);
});
for (var i=0; i<sortByPrice.length; i++)
{
document.write(sortByPrice[i].h_id+' '+sortByPrice[i].city+' '
+sortByPrice[i].state+' '
+sortByPrice[i].zip+' '+sortByPrice[i].price);
document.write("<br>");
}
答案 26 :(得分：0)
对多个数组对象字段进行排序。
在arrprop数组中输入您的字段名称，例如["a","b","c"]
然后传递我们要排序的第二个参数arrsource实际来源。
function SortArrayobject(arrprop,arrsource){
arrprop.forEach(function(i){
arrsource.sort(function(a,b){
return ((a[i] < b[i]) ? -1 : ((a[i] > b[i]) ? 1 : 0));
});
});
return arrsource;
}
答案 27 :(得分：0)
使用以下代码创建函数并基于输入进行排序
var homes = [{
"h_id": "3",
"city": "Dallas",
"state": "TX",
"zip": "75201",
"price": "162500"
}, {
"h_id": "4",
"city": "Bevery Hills",
"state": "CA",
"zip": "90210",
"price": "319250"
}, {
"h_id": "5",
"city": "New York",
"state": "NY",
"zip": "00010",
"price": "962500"
}];
function sortList(list,order){
if(order=="ASC"){
return list.sort((a,b)=>{
return parseFloat(a.price) - parseFloat(b.price);
})
}
else{
return list.sort((a,b)=>{
return parseFloat(b.price) - parseFloat(a.price);
});
}
}
sortList(homes,'DESC');
console.log(homes);
答案 28 :(得分：0)
您好，在阅读完本文后，我根据自己的需求制作了一个sortComparator，其功能是比较多个json属性，我希望与您分享。
此解决方案仅按升序比较字符串，但可以轻松扩展每个属性的解决方案以支持：反向排序，其他数据类型，使用区域设置，强制转换等
var homes = [{
"h_id": "3",
"city": "Dallas",
"state": "TX",
"zip": "75201",
"price": "162500"
}, {
"h_id": "4",
"city": "Bevery Hills",
"state": "CA",
"zip": "90210",
"price": "319250"
}, {
"h_id": "5",
"city": "New York",
"state": "NY",
"zip": "00010",
"price": "962500"
}];
// comp = array of attributes to sort
// comp = ['attr1', 'attr2', 'attr3', ...]
function sortComparator(a, b, comp) {
// Compare the values of the first attribute
if (a[comp[0]] === b[comp[0]]) {
// if EQ proceed with the next attributes
if (comp.length > 1) {
return sortComparator(a, b, comp.slice(1));
} else {
// if no more attributes then return EQ
return 0;
}
} else {
// return less or great
return (a[comp[0]] < b[comp[0]] ? -1 : 1)
}
}
// Sort array homes
homes.sort(function(a, b) {
return sortComparator(a, b, ['state', 'city', 'zip']);
});
// display the array
homes.forEach(function(home) {
console.log(home.h_id, home.city, home.state, home.zip, home.price);
});
，结果是
$ node sort
4 Bevery Hills CA 90210 319250
5 New York NY 00010 962500
3 Dallas TX 75201 162500
和另一种
homes.sort(function(a, b) {
return sortComparator(a, b, ['city', 'zip']);
});
结果
$ node sort
4 Bevery Hills CA 90210 319250
3 Dallas TX 75201 162500
5 New York NY 00010 962500
答案 29 :(得分：0)
homes.sort(function(a, b){
var nameA=a.prices.toLowerCase(), nameB=b.prices.toLowerCase()
if (nameA < nameB) //sort string ascending
return -1
if (nameA > nameB)
return 1
return 0 //default return value (no sorting)
})
答案 30 :(得分：0)
如果您想使用它，我最近编写了一个通用功能来管理它。
/**
* Sorts an object into an order
*
* @require jQuery
*
* @param object Our JSON object to sort
* @param type Only alphabetical at the moment
* @param identifier The array or object key to sort by
* @param order Ascending or Descending
*
* @returns Array
*/
function sortItems(object, type, identifier, order){
var returnedArray = [];
var emptiesArray = []; // An array for all of our empty cans
// Convert the given object to an array
$.each(object, function(key, object){
// Store all of our empty cans in their own array
// Store all other objects in our returned array
object[identifier] == null ? emptiesArray.push(object) : returnedArray.push(object);
});
// Sort the array based on the type given
switch(type){
case 'alphabetical':
returnedArray.sort(function(a, b){
return(a[identifier] == b[identifier]) ? 0 : (
// Sort ascending or descending based on order given
order == 'asc' ? a[identifier] > b[identifier] : a[identifier] < b[identifier]
) ? 1 : -1;
});
break;
default:
}
// Return our sorted array along with the empties at the bottom depending on sort order
return order == 'asc' ? returnedArray.concat(emptiesArray) : emptiesArray.concat(returnedArray);
}