Question

message="this is fun"

def translate(robber):
    consonants=['bcdfghjklmnpqrstvwxz']
    for letters in robber:
        if letters in consonants:
            return (letters + 'o' + letters)
            continue
        else:
            return translate

print translate(message)

尝试创建一个带有字符串并将其转换为强盗语言的嵌套循环。有谁知道我的代码中我做错了什么？

Answer 1

您需要构建一个新的强盗名称，然后返回：

def translate(robber):
    consonants = 'bcdfghjklmnpqrstvwxz'
    new_robber = ''
    for letter in robber:
        if letter in consonants:
            new_robber += letter + 'o' + letter
        else:
            new_robber += letter
    return new_robber

奖金答案实际上包含一个嵌套循环（但不是很好的python）：

def translate(robber):
    consonants = 'bcdfghjklmnpqrstvwxz'
    new_robber = ''
    for letter in robber:
        for consonant in consonants:
            if consonant == letter:
                letter += 'o' + letter
                break
        new_robber += letter
    return new_robber

Answer 2

使用print ... for python 2.7

def translate(s):
  consonants = 'bcdfghjklmnpqrstvwxz'
  return ''.join(x + 'o' + x if x in consonants else x for x in s)

print(translate("robbers language"))

字符串翻译强盗的语言

2 个答案: