Question

我希望在public static changesMade: Subject<any> = new Subject(); //inside constructor the following ParentComponent.changesMade.subscribe(res => { //call your method here, with the res (someData) you receive from child this.doThisWhenChildEmits(res); });更改时从数据库获取订单信息及其日期。

请用书面代码帮助我，因为我还是PHP新手。

CODE：

public clickToSendBack(){
   // send the data to parent
   ParentComponent.changesMade.next(someData)
}

Answer 1

如果我理解正确：你想要执行一些PHP代码，用数据库日期检查数据日期保存在数据库中。当datepicker输入字段发生更改时，您希望执行该PHP代码

要完成此操作，您可以使用Ajax调用。通过Ajax调用，您可以从php文件中获取结果，而无需重新加载页面。我建议使用Jquery和Bootstrap datapicker。当然你可以使用另一个datepicker插件，但是你需要查看该文档如何在日期更改时执行js函数。

使用Bootstrap数据贴图，它将如下所示

$('#datepicker').datepicker().on('changeDate', function () {
    //js code executed when #datepicker data changes

    //get te data
    var datepickerDate = $('#datepicker').val(); //date of datepicker
    var data = {datepickerDate: datepickerDate};
    var json = JSON.stringify(data);
    var url = "check_date.php" //URL to a php file, I would call it check_date.php

    //set up ajax call
    $.ajax({
      method: "POST",
      url: url,
      data: {data: json}
    })
    .done(function( result ) {//when the ajax call was successfully executed
      //we will add things here later
    });
});

这会将datepicker inputvield的日期发送到名为check_data.php的php文件

check_data.php将如下所示：

<?php
if(isset($_POST['data'])) {//check if data has been send
  /* we made a json of data so we first need to decode the json. 
  We can access data with $_POST because we used the method POST in the ajax call*/
  $data = json_decode($_POST['data']);

  /* now define the variable $date to the $date you send with POST */
  $date = $data->datepickerDate;
  /* now you need the date saved in your database */
  $DBdate = "Put your database date here";

  /* now you can check if they are equal */
  if($date == $DBdate) {
    echo 'true'; //when dates are equal
  } else {
    echo 'false'; //when dates are not equal
  }
}?>

此文件现在将返回true或false，具体取决于datebasedate是否等于datepicker-date

这意味着我们现在可以对ajax调用完成时的操作进行编程

.done(function( result ) {//when the ajax call was successfully executed
  //result will be the result the php file gives us (true or false)
  if(result == true) {
    //display your table
  } else {
    //do nothing or inform the user that the dates do not match
  }
});

如果使用mysqli和php在datepicker中的date = date中的日期，如何在datepicker上显示表内容？

1 个答案: