我怎样才能在第二张桌子上获得最新的付款日期？

Question

这是我当前的查询

$ sql =＆＃34; SELECT full_name，amount，                  SUM（payments。payment_amount）为totalPayment，                  borrowers。amount - SUM（payments。payment_amount）为totalBalance，                  date_borrowed，borrowers。id                  来自borrowers                   LEFT JOIN payments点击borrowers。id = payments。borrower_id                   GROUP BY borrowers。id ORDER BY date_borrowed DESC＆＃34;;

第一张桌子;

第二张表;

我的桌子;

Answer 1

联接将为您提供所有付款记录，您只需要最后一个。做一个子查询：

$sql = "SELECT 
   full_name, amount, SUM(payments.payment_amount) as totalPayment,
   borrowers.amount - SUM(payments.payment_amount) as totalBalance, 
   date_borrowed, borrowers.id,
   (SELECT payment_date FROM payments 
       WHERE borrowers.id=payments.borrower_id 
       ORDER BY payment_date DESC LIMIT 0,1) 
       AS last_payment
    FROM borrowers GROUP BY borrowers.id ORDER BY date_borrowed DESC";