Question

// table main_lookup

const main_lookup=DB.connection.define('main_lookup',{

main_lookup_name: {
    type :Sequelize.STRING,
    primaryKey: true,
    allowNull: false
},

value:{
type:Sequelize.JSON,
allowNull:false,
}

});

//表2

const school_lookup= DB.connection.define('school_lookup',{


school_id : {
    type :Sequelize.STRING,
    allowNull: false,
    references: {            
         model: schools,
         key: 'school_id'
    }
},  
lookup_name: {
    type :Sequelize.STRING,
    unique: true,
    allowNull: false
},
value: {
type: Sequelize.JSON,
allowNull: false,
}


});

我需要将数据从main_lookup表发送到学校查找数据

school_id // that is given by me 
lookup_name // that is copy from main_lookup
value // that is copy from main_look_up

示例主查找// table1

main_lookup_name value
---------------- -----
language         ['english','tamil']
subject          ['social','maths']

该解决方案类似于此

之后的内容

school_lookup // table2 //needed 

school_id lookup    value
--------- ------    -----
cit       language  ['english','tamil']
cit       subject   ['social','maths']

我需要通过简单的方式提供帮助

Answer 1

您可以使用原始查询执行相同的操作。

var Sequelize = require('sequelize');
var sequelize = new Sequelize('database', 'username', 'password');

sequelize.query("insert into <table1> select * from <table2>", { type:Sequelize.QueryTypes.SELECT})
.then(function(results) {
console.log(results)            // or do whatever you want
})

Answer 2

我认为你正在使用sequelize，就像人们如何使用microsoft excel或microsoft访问一样。你可以简单地在续集中建立关系。这是代码

//校模型

    const School=Sequelize.define('school',{

        name: {
            type :Sequelize.STRING,
            allowNull: false
        }
    });

//受试者

    const Subject= Sequelize.define('subject',{

        type: {
            type :Sequelize.STRING,
            unique: true,
            allowNull: false
        },
        value: {
            type: Sequelize.ARRAY,
            allowNull: false,
        }
    });

//数据库

    const School = require('./path_to_schoolmodel');
    const Subject = require('./path_to_subjectmodel');

    Subject.belongsTo(School);
    School.hasMany(Subject);

学校模式

    id name
    -- ---------------------
    1  'fullstack academy'
    2  'app academy'

    Subject model
    id type      value                schoolID
    -- --------- -------------------- ------------------
    1  language  ['english','tamil']  2
    2  subject   ['social','maths']   1

如果您设置模型关系，您应该能够看到这样的数据。

然后在服务器端使用Sequelize模型查询时。

    const School = require('./path_to_schoolmodel');
    const Subject = require('./path_to_subjectmodel');
    School.findAll({
         include:[ Subject ]
       })
       .then(console.log)
       .catch(console.error)

你的console.log应该返回类似

的内容

    [
        {
            id: 1,
            name: 'fullstack academy'
            subjects: [{
                id: 2,
                type: 'subject',
                value: [
                   'socials', 'maths'
                ]
            }]
        },
        {
            id: 2,
            name: 'app academy'
            subjects: [{
                id: 1,
                type: 'language',
                value: [
                   'english', 'tamil'
                ]
            }]
        },
    ]

如何使用sequalize从另一个表中插入所有值

2 个答案: