Question

我试图一次性执行以下声明。就像我们使用INSERT ALL在一次执行中插入行一样。有没有办法可以在一次执行中执行以下两个语句（使用INSERT ALL）。

INSERT
INTO TABLE_a
  (
    COLUMN_1,
    COLUMN_2,
    COLUMN_3,
    COLUMN_4,
    COLUMN_5,
    COLUMN_6,
    COLUMN_7,
    COLUMN_8
  )
SELECT 1234, -- unique id for this insertion
    COLUMN_2,
    COLUMN_3,
    COLUMN_4,
    COLUMN_5,
    COLUMN_6,
    COLUMN_7,
    COLUMN_8
FROM TABLE_B
WHERE COLUMN_9=1;
INSERT
INTO TABLE_a
  (
    COLUMN_1,
    COLUMN_2,
    COLUMN_3,
    COLUMN_4,
    COLUMN_5,
    COLUMN_6,
    COLUMN_7,
    COLUMN_8
  )
SELECT 1235, -- unique id for this insertion
    COLUMN_2,
    COLUMN_3,
    COLUMN_4,
    COLUMN_5,
    COLUMN_6,
    COLUMN_7,
    COLUMN_8
FROM TABLE_B
WHERE COLUMN_9=2;

Answer 1

当然，您可以使用in clause收集Id 1和2

并使用decode在1234和1235之间有所不同：

INSERT
INTO TABLE_a
  (
    COLUMN_1,
    COLUMN_2,
    COLUMN_3,
    COLUMN_4,
    COLUMN_5,
    COLUMN_6,
    COLUMN_7,
    COLUMN_8
  )
SELECT decode(COLUMN_9,1,1234,2,1235),
    COLUMN_2,
    COLUMN_3,
    COLUMN_4,
    COLUMN_5,
    COLUMN_6,
    COLUMN_7,
    COLUMN_8
FROM TABLE_B
WHERE COLUMN_9 in (1,2);

Answer 2

为什么不使用OR条件？如果它适合你，试试这个

INSERT
INTO TABLE_a
  (
    COLUMN_1,
    COLUMN_2,
    COLUMN_3,
    COLUMN_4,
    COLUMN_5,
    COLUMN_6,
    COLUMN_7,
    COLUMN_8
  )
SELECT CASE WHEN COLUMN_9 = 1 THEN 1234 WHEN COLUMN_9 = 2 THEN 1235 END,
    COLUMN_2,
    COLUMN_3,
    COLUMN_4,
    COLUMN_5,
    COLUMN_6,
    COLUMN_7,
    COLUMN_8
FROM TABLE_B
WHERE COLUMN_9=1 OR COLUMN_9=2;

使用@ strong

建议的 DECODE() 功能

INSERT
INTO TABLE_a
  (
    COLUMN_1,
    COLUMN_2,
    COLUMN_3,
    COLUMN_4,
    COLUMN_5,
    COLUMN_6,
    COLUMN_7,
    COLUMN_8
  )
SELECT DECODE(COLUMN_9,1,1234,2,1235)
    COLUMN_2,
    COLUMN_3,
    COLUMN_4,
    COLUMN_5,
    COLUMN_6,
    COLUMN_7,
    COLUMN_8
FROM TABLE_B
WHERE COLUMN_9=1 OR COLUMN_9=2;

Answer 3

您可以将INSERT INTO ... SELECT与联合查询一起使用：

INSERT INTO TABLE_a (COLUMN_1, COLUMN_2, COLUMN_3, COLUMN_4, COLUMN_5, COLUMN_6,
    COLUMN_7, COLUMN_8)
SELECT
    1234, COLUMN_2, COLUMN_3, COLUMN_4, COLUMN_5, COLUMN_6, COLUMN_7, COLUMN_8
FROM TABLE_B
WHERE COLUMN_9 = 1
UNION ALL
SELECT
    1235, COLUMN_2, COLUMN_3, COLUMN_4, COLUMN_5, COLUMN_6, COLUMN_7, COLUMN_8
FROM TABLE_B
WHERE COLUMN_9 = 2

与原始方法相比，这种方法有一个明显的优势。有了这个答案，整个插入就会发生在一个声明中。

从另一个表

3 个答案: