我写了以下函数:
Private Sub TextBox5_Change()
ActiveSheet.ListObjects("nameofthetable").Range.AutoFilter Field:=3, Criteria1:=TextBox5.Value
End Sub
这个想法是A是一个比B更宽的矩阵。我想通过重复自身来扩大B(当A的行长不完全除以B的那个时也应该工作。)
如果你运行上面的代码,你会得到:
A = tf.constant([[1,2,3,4,4,5,6,7,2],[4,5,6,6,4,5,6,7,2],[6,7,8,9,4,5,6,7,2]])
B = tf.constant([[19,15],
[18,14],
[17,13]])
diff = A.get_shape()[1] - B.get_shape()[1]
Bt = tf.transpose(B)
for idx in range(diff):
col = tf.gather_nd(Bt, [[idx]])
Bt = tf.concat(0, [Bt, col])
result = tf.transpose(Bt)
with tf.Session() as sess:
res = sess.run(result)
print(res)
关于如何通过使用张量流函数来实现这一点的任何想法?