我想(仅在使用Objective-C的iOS中)获取具有电话号码的联系人,但我该怎么做?我试图在下面的代码中形成谓词,但显然这不起作用。
contacts = [contactStore unifiedContactsMatchingPredicate:[NSPredicate predicateWithFormat:@"phoneNumbers <> nil"] keysToFetch:KEYS error:nil];
那么,这样做的正确方法是什么?谢谢你的帮助!
答案 0 :(得分:2)
#import <Contacts/Contacts.h>
CNContactStore *store = [[CNContactStore alloc] init];
[store requestAccessForEntityType:CNEntityTypeContacts completionHandler:^(BOOL granted, NSError * _Nullable error) {
if (granted == YES) {
//keys with fetching properties
NSArray *keys = @[CNContactFamilyNameKey, CNContactGivenNameKey, CNContactPhoneNumbersKey, CNContactImageDataKey, CNContactEmailAddressesKey];
CNContactFetchRequest *request = [[CNContactFetchRequest alloc] initWithKeysToFetch:keys];
request.sortOrder = CNContactSortOrderGivenName;
request.unifyResults = YES;
NSError *error;
__block NSString* email;
BOOL success = [store enumerateContactsWithFetchRequest:request error:&error usingBlock:^(CNContact * __nonnull contact, BOOL * __nonnull stop)
{
if (error) {
NSLog(@"error fetching contacts %@", error);
} else {
NSString *fullName;
NSString* phone;
// for (CNContact *contact in cnContacts) {
DeviceContact *aContact = [DeviceContact new];
// copy data to my custom Contacts class.
NSString *firstName = contact.givenName;
NSString *lastName = contact.familyName;
if (lastName == nil) {
fullName=[NSString stringWithFormat:@"%@",firstName];
}else if (firstName == nil){
fullName=[NSString stringWithFormat:@"%@",lastName];
}
else{
fullName=[NSString stringWithFormat:@"%@ %@",firstName,lastName];
}
if ([firstName trim].length > 0) {
aContact.nameForSorting = firstName; // 141116
}else if ([lastName trim].length>0 && aContact.nameForSorting.length<=0) {
aContact.nameForSorting = lastName; // 141116
}
aContact.name = fullName;
if (contact.phoneNumbers!=nil && [contact.phoneNumbers count]>0) {
for (CNLabeledValue *label in contact.phoneNumbers) {
phone = [CommonUtils removeAllSpecialCharactersFromPhoneNumber:[label.value stringValue]];
if ([phone length] > 0) {
[aContact.phoneNumber addObject:phone];
}
}
}
////Get all E-Mail addresses from contacts
/// if ([CommonUtils checkIsNullObject:[contact emailAddresses]] && [[contact emailAddresses] count]>0) {
for (CNLabeledValue *label in contact.emailAddresses) {
email = label.value;
if ([email length] > 0)
{
[aContact.email addObject:email];
}
}
// }
// 141116
if ([aContact.name trim].length <= 0) {
if (aContact.email.count>0) {
aContact.name = [aContact.email objectAtIndex:0];
}else if (aContact.phoneNumber.count>0){
aContact.name = [aContact.phoneNumber objectAtIndex:0];
}
}
if ([aContact.nameForSorting trim].length <= 0){
if (aContact.email.count>0) {
aContact.nameForSorting = [aContact.email objectAtIndex:0];
}else if (aContact.phoneNumber.count>0){
aContact.nameForSorting = [aContact.phoneNumber objectAtIndex:0];
}
}
[self.arrAllContacts addObject:aContact];
}
}];
if(success){
dispatch_async(dispatch_get_main_queue(), ^{
[CommonUtils hideLoader];
completionhandler(self.arrAllContacts);
});
}
}
else
{
// [CommonUtils showAlertMessageWithMessage:@"fdfdggfsgfdgfd" withDelegate:self withCancelTitle:OKAY isOtherButton:NO withOtherButtonTitle:nil withTag:0];
[CommonUtils hideLoader];
}
}];
答案 1 :(得分:0)
使用以下方法并导入
#import <AddressBook/AddressBook.h>
#import <Contacts/Contacts.h>
-(void)contactsDetailsFromPhoneContactBook{
CNContactStore *store = [[CNContactStore alloc] init];
[store requestAccessForEntityType:CNEntityTypeContacts completionHandler:^(BOOL granted, NSError * _Nullable error) {
if (granted == YES) {
//keys with fetching properties
NSArray *keys = @[CNContactFamilyNameKey,CNContactGivenNameKey];
NSString *containerId = store.defaultContainerIdentifier;
NSPredicate *predicate = [CNContact predicateForContactsInContainerWithIdentifier:containerId];
NSError *error;
NSArray *cnContacts = [store unifiedContactsMatchingPredicate:predicate keysToFetch:keys error:&error];
if (error) {
NSLog(@"error fetching contacts %@", error);
} else {
NSString *fullName;
NSString *firstName;
NSString *lastName;
for (CNContact *contact in cnContacts) {
// copy data to my custom Contacts class.
firstName = contact.givenName;
lastName = contact.familyName;
if (lastName == nil) {
fullName=[NSString stringWithFormat:@"%@",firstName];
}else if (firstName == nil){
fullName=[NSString stringWithFormat:@"%@",lastName];
}
else{
fullName=[NSString stringWithFormat:@"%@ %@",firstName,lastName];
}
[self.contactsArray addObject:fullName];
NSLog(@"working or not %@",self.contactsArray);
}
}
}
}];
}
答案 2 :(得分:0)
无法过滤掉没有电话号码(或其他属性)的联系人。在我们阅读的文档中:
CNContact Predicates
谓词匹配联系人。 您只能使用这些谓词 使用CNContactStore和CNContactFetchRequest。
- predicateForContactsMatchingName:返回谓词以查找与指定名称匹配的联系人。
- predicateForContactsWithIdentifiers:返回谓词以查找与指定标识符匹配的联系人。
- predicateForContactsInGroupWithIdentifier:返回谓词以查找指定组中成员的联系人。
- predicateForContactsInContainerWithIdentifier:返回谓词以查找指定容器中的联系人。
另外:
不支持复合谓词。
因此,进行过滤的唯一方法是省略向结果数组添加没有电话号码的联系人。例如,可以在enumerateContactsWithFetchRequest
。