这是kmeans算法的一个实现,我从kmeans scikit文档和讨论kmeans的博客文章中放在一起:
#http://scikit-learn.org/stable/modules/generated/sklearn.cluster.KMeans.html
#http://fromdatawithlove.thegovans.us/2013/05/clustering-using-scikit-learn.html
from sklearn.cluster import KMeans
import numpy as np
from matplotlib import pyplot
X = np.array([[10, 2 , 9], [1, 4 , 3], [1, 0 , 3],
[4, 2 , 1], [4, 4 , 7], [4, 0 , 5], [4, 6 , 3],[4, 1 , 7],[5, 2 , 3],[6, 3 , 3],[7, 4 , 13]])
kmeans = KMeans(n_clusters=3, random_state=0).fit(X)
k = 3
kmeans.fit(X)
labels = kmeans.labels_
centroids = kmeans.cluster_centers_
for i in range(k):
# select only data observations with cluster label == i
ds = X[np.where(labels==i)]
# plot the data observations
pyplot.plot(ds[:,0],ds[:,1],'o')
# plot the centroids
lines = pyplot.plot(centroids[i,0],centroids[i,1],'kx')
# make the centroid x's bigger
pyplot.setp(lines,ms=15.0)
pyplot.setp(lines,mew=2.0)
pyplot.show()
print(kmeans.cluster_centers_.squeeze())
如何打印/访问每个k簇的数据点。
if k = 3 :
cluster 1 : [10, 2 , 9], [1, 4 , 3], [1, 0 , 3]
cluster 2 : [4, 0 , 5], [4, 6 , 3],[4, 1 , 7],[5, 2 , 3],[6, 3 , 3],[7, 4 , 13]
cluster 3 : [4, 2 , 1], [4, 4 , 7]
阅读http://scikit-learn.org/stable/modules/generated/sklearn.cluster.KMeans.html kmeans
对象上没有属性或方法吗?
更新:
kmeans.labels_
返回array([1, 0, 2, 0, 2, 2, 0, 2, 0, 0, 1], dtype=int32)
但是,这如何显示3个集群中每个集群的数据点?
答案 0 :(得分:1)
如果您使用拟合_labels
对象的KMeans
属性,您将获得每个训练向量的群集分配数组。标签数组的顺序与您的训练数据相同,因此您可以压缩它们或为每个唯一标签执行numpy.where()。
答案 1 :(得分:1)
要在k-means聚类后访问数据点:
添加了代码:
sortedR = sorted(result, key=lambda x: x[1])
sortedR
完整代码:
from sklearn.cluster import KMeans
import numpy as np
from matplotlib import pyplot
X = np.array([[10, 2 , 9], [1, 4 , 3], [1, 0 , 3],
[4, 2 , 1], [4, 4 , 7], [4, 0 , 5], [4, 6 , 3],[4, 1 , 7],[5, 2 , 3],[6, 3 , 3],[7, 4 , 13]])
kmeans = KMeans(n_clusters=3, random_state=0).fit(X)
k = 3
kmeans = KMeans(n_clusters=k)
kmeans.fit(X)
labels = kmeans.labels_
centroids = kmeans.cluster_centers_
for i in range(k):
# select only data observations with cluster label == i
ds = X[np.where(labels==i)]
# plot the data observations
pyplot.plot(ds[:,0],ds[:,1],'o')
# plot the centroids
lines = pyplot.plot(centroids[i,0],centroids[i,1],'kx')
# make the centroid x's bigger
pyplot.setp(lines,ms=15.0)
pyplot.setp(lines,mew=2.0)
pyplot.show()
result = zip(X , kmeans.labels_)
sortedR = sorted(result, key=lambda x: x[1])
sortedR