Question

我有两个数组，其中包含我要从员工数组中删除的ID列表。

在Java脚本中执行此操作的最佳方法是什么？我可以使用任何ES6语法

{
  "excludeIDArray": [
    1,
    3,
    4
  ]
}



{
  "employee": [
    {
      "id": "1",
      "name": "joe"
    },
    {
      "id": "2",
      "name": "john"
    },
    {
      "id": "3",
      "name": "mike"
    },
    {
      "id": "4",
      "name": "alex"
    },
    {
      "id": "5",
      "name": "sean"
    }
  ]
}

我希望输出是一个看起来像

的数组

{
  "employee": [
    {
      "id": "2",
      "name": "john"
    },
    {
      "id": "5",
      "name": "sean"
    }
  ]
}

Answer 1

只需使用Array.prototype.filter，Array.prototype.indexOf和parseInt（将字符串ID转换为数字）。

const exc = {"excludeIDArray":[1,3,4]}
const inObj = {"employee":[{"id":"1","name":"joe"},{"id":"2","name":"john"},{"id":"3","name":"mike"},{"id":"4","name":"alex"},{"id":"5","name":"sean"}]}

const outObj = { 
  employee: inObj.employee.filter(e => exc.excludeIDArray.indexOf(parseInt(e.id, 10)) === -1)
}

console.log(outObj);

您也可以使用Array.prototype.includes（如果可用）代替Array.prototype.indexOf，因为它更具可读性

e => !exc.excludeIDArray.includes(parseInt(e.id, 10))

另一种选择是将您的排除数组转换为Set，这样可以获得更好的（O(1)）效果

const exc = {"excludeIDArray":[1,3,4]}
const inObj = {"employee":[{"id":"1","name":"joe"},{"id":"2","name":"john"},{"id":"3","name":"mike"},{"id":"4","name":"alex"},{"id":"5","name":"sean"}]}

const exclude = new Set(exc.excludeIDArray)
const outObj = {
  employee: inObj.employee.filter(e => !exclude.has(parseInt(e.id, 10)))
}
console.info(outObj)

Answer 2

使用地图进行过滤而不是indexOf，以便更快地进行线性时间过滤

var exclusion = {"excludeIDArray": [1, 3, 4]};

var data = {"employee":[{"id":"1","name":"joe"},{"id":"2","name":"john"},{"id":"3","name":"mike"},{"id":"4","name":"alex"},{"id":"5","name":"sean"}]};
	
var exclusionMap = {};
exclusion.excludeIDArray.forEach(excludeId=>{exclusionMap[excludeId] = 1});
var filteredEmployees = data.employee.filter(employee=>{return exclusionMap[employee.id] === undefined});
console.log(filteredEmployees);

从Java脚本中排除数组列表中的ID列表

2 个答案: