如何从Elastic Search中的query_string中排除一组id？

Question

我有一个像这样的查询字符串：

"(( name_first.raw:goda )) AND !( _uid:*566ade1cec8d83647a000061* OR _uid:*566ade1cec8d83647a000062* OR _uid:*566ade1cec8d83647a000063* OR _uid:*566ade1cec8d83647a000064*)"

如何以更有效的方式编写此查询？

Answer 1

我认为这会奏效，

GET /yourindex/yourType/_search
{
    "query": {
        "filtered": {
           "query": {
           "match": {
              "name_first.raw": "goda"
           }
           },
           "filter": {
               "bool": {
                   "must_not": [
                      {
                          "terms": {
                             "_uid": [
                                "566ade1cec8d83647a000061",
                                "566ade1cec8d83647a000062",
                                "566ade1cec8d83647a000063"
                             ]
                          }
                      }
                   ]
               }
           }
        }
    }
}

Answer 2

您可以使用以下查询：

POST <index>/<type>/_search
{
  "query": {
    "filtered": {
      "query": {
        "term": {
          "name_first.raw": "goda"
        }
      },
      "filter": {
        "bool": {
          "must_not": [
            {
              "terms": {
                "_uid": [
                  "566ade1cec8d83647a000061",
                  "566ade1cec8d83647a000062",
                  "566ade1cec8d83647a000063"
                ]
              }
            }
          ]
        }
      }
    }
  }
}

Answer 3

这应该有用，（+ =＆gt;＆＃34;必须＆＃34;和- =＆gt;＆＃34; must_not＆＃34;）

"+name_first.raw:goda -_uid:*566ade1cec8d83647a000061* -_uid:*566ade1cec8d83647a000062* -_uid:*566ade1cec8d83647a000063*  -_uid:*566ade1cec8d83647a000064*"

令我担心的是，领先通配符的处理可能会真正减缓这种情况。你绝对需要通配符吗？如果您发现自己需要对此进行优化，并且可以开始使用DSL，请查看post_filter以了解排除标准。