Question

我有

g = [[1], [2], [3], [4], [5], [6]]
c = [[9], [8], [7], [6], [5], [4]]

我需要得到

t = [[1,9], [2,8], [3,7], [4,6], [5,5], [6,4]]

请帮帮我

Answer 1

使用此处的zip() function来组合嵌套列表的元素：

t = [a + b for a, b in zip(g, c)]

演示：

>>> g = [[1], [2], [3], [4], [5], [6]]
>>> c = [[9], [8], [7], [6], [5], [4]]
>>> [a + b for a, b in zip(g, c)]
[[1, 9], [2, 8], [3, 7], [4, 6], [5, 5], [6, 4]]

使用iterative zip() function from Python 3 / itertools：

可以提高效率

try:
    from future_builtins import zip
except ImportError:
    pass

t = [a + b for a, b in zip(g, c)]

只有在希望代码同时适用于Python 2和3时才需要try..except。

Answer 2

另一个没有zip的选项，使用list comprehension：

>>> g = [[1], [2], [3], [4], [5], [6]]
>>> c = [[9], [8], [7], [6], [5], [4]]
>>> result = [ [g[i][0], c[i][0]] for i in range(min([len(g), len(c)])) ]
>>> print(result)
[[1, 9], [2, 8], [3, 7], [4, 6], [5, 5], [6, 4]]
>>>

Answer 3

你好，如果你使用的是Python 2.7，你可以使用zip

g = [[1], [2], [3], [4], [5], [6]]
c = [[9], [8], [7], [6], [5], [4]]
t = zip(g, c)
[([1], [9]), ([2], [8]), ([3], [7]), ([4], [6]), ([5], [5]), ([6], [4])]

如何组合两个列列表？

3 个答案: