Question

我有两个清单列表 -

dates = [[＆＃39; 22/08/15＆＃39;]，[＆＃39; 24/08/15＆＃39;，＆＃39; 0900-1045＆＃39;，＆＃39; 1045-1100＆＃39;，＆＃39; 1100-1200＆＃39;，＆＃39; 1300-1430＆＃39;，＆＃39; 1430-1450＆＃39;，＆＃39; 1450-1550＆＃39; ]，..........

data1 = [[＆＃39; Tuesday＆＃39;]。[＆＃39; Thursday＆＃39;，＆＃39; Room 5＆＃39;，＆＃39; Room 1＆＃39;，＆＃39 ; 1号房间＆＃39; ，＆＃39; Room 2＆＃39;，＆＃39; Room 3＆＃39;，＆＃39; Room 5＆＃39;]，........

每个列表的子列表大小相同但长度不同，即子列表的长度不同，但列表日期和数据是对称的。

我想把两个＆＃34;按位＆＃34;给予 -

[[＆＃39; 22/08/15 Tuesday＆＃39;]，[＆＃39; 24/08/15 Thursday＆＃39;，＆＃39; 0900-1045 Room 5＆＃39;，＆＃ 39; 1045-1100房间1＆＃39;，.....

我已经成功地使用了一个非常繁忙的嵌套循环，但它似乎非常复杂，所以我认为必须有更好的方法。

以下是我到目前为止所做的尝试：

    x = 0
    print dates
    print data1
    while x < len(dates):
        b = 0
        print b
        while b < len(dates[x]):
            print dates[x][b]
            print data1[x][b]
            result = dates[x][b] + ' ' + data1[x][b]
            data2.append(result)  
            b = b + 1
        x = x + 1

Answer 1

你想要的是：

[[' '.join(p) for p in zip(d, c)] for d, c in zip(dates, comments)]

这是用给定数据测试的：

>> dates = [['22/08/15'], ['24/08/15', '0900-1045', '1045-1100', '1100-1200', '1300-1430', '1430-1450', '1450-1550']]
>> comments = [['Tuesday'], ['Thursday','Room 5', 'Room 1', 'Room 1' ,'Room 2', 'Room 3', 'Room 5']]
>> [[' '.join(p) for p in zip(d, c)] for d, c in zip(dates, comments)]
[['22/08/15 Tuesday'], ['24/08/15 Thursday', '0900-1045 Room 5', '1045-1100 Room 1', '1100-1200 Room 1', '1300-1430 Room 2', '1430-1450 Room 3', '1450-1550 Room 5']]

结合两个列表列表 - 按位

1 个答案: