2和之和的总和

Question

我需要2个和数之和的帮助。 好吧，我有一个表显示用户总数的表。 在表格末尾，我需要制作显示所有数字总和的行。

表：

所以在蓝线上我需要所有数字的总和。 我的代码：

 $groupQuery =
    "SELECT r.broj_rac AS racun, COUNT(stavka) AS stavka, d.naziv1 AS dobavljac, SUM(iznos_osnovica) AS osnovica, SUM(iznos_porez) AS porez, SUM(moze_se_odbiti) AS odbiti, SUM(nemoze_se_odbiti) AS neodbiti, SUM(neoporezivo) AS neoporezivo, SUM(ukupno) AS ukupno1, r.sveukupno AS sveukupno 
    FROM racuni AS r
    LEFT JOIN dobavljaci AS d
    ON d.sifra = r.dobavljac
    WHERE partner = '".$_SESSION['sifra_partnera']."'
    GROUP by broj_rac";

是否可以制作类似SUM(SUM(ukupno AS ukupno1) AS ukupno2)的内容？

Answer 1

看起来你想要添加一个总行，而不是像其他答案所建议的那样添加总和列，所以如果你只想包含一个总计osnovica和{{1}的行，那么这样的话应该有效}值：

porez

在$groupQuery = SELECT r.broj_rac AS racun, COUNT(stavka) AS stavka, d.naziv1 AS dobavljac, SUM(iznos_osnovica) AS osnovica, SUM(iznos_porez) AS porez, SUM(moze_se_odbiti) AS odbiti, SUM(nemoze_se_odbiti) AS neodbiti, SUM(neoporezivo) AS neoporezivo, SUM(ukupno) AS ukupno1, r.sveukupno AS sveukupno FROM racuni AS r LEFT JOIN dobavljaci AS d ON d.sifra = r.dobavljac WHERE partner = '".$_SESSION['sifra_partnera']."' GROUP by broj_rac UNION SELECT 'TOTAL' AS racun, '' AS stavka, '' AS dobavljac, SUM(iznos_osnovica) AS osnovica, SUM(iznos_porez) AS porez, '' AS odbiti, '' AS neodbiti, '' AS neoporezivo, '' AS ukupno1, '' AS sveukupno FROM racuni AS r LEFT JOIN dobavljaci AS d ON d.sifra = r.dobavljac WHERE partner = '".$_SESSION['sifra_partnera']."'" 的后半部分，您还可以在您希望在总行中汇总的任何其他字段上执行汇总功能，例如UNION或SUM(ukupno) AS ukupno1 AVG(ukupno) AS ukupno1的总和或平均值。

Answer 2

尝试以下查询

SELECT 
(
    SUM(COL_1)
  + SUM(COL_2)
  + SUM(COL_3)
) as `Total` 
FROM TABLE_NAME 

Answer 3

你可以做到

SELECT 
   Val1,
   Val2,
   Val3,
   (Val1 + Val2 + Val3) as 'Total'
FROM MyTable

或者如果你只想要一行：

SELECT 
   SUM(Val1) as 'Val1',
   SUM(Val2) as 'Val2',
   SUM(Val3) as 'Val3',
   (SUM(Val1) + SUM(Val2) + SUM(Val3)) as 'Total'
FROM MyTable

Answer 4

尝试以下查询

SELECT 
    (
        SUM(COL_1)
      + SUM(COL_2)
      + SUM(COL_3)
    ) as `Total` 
FROM TABLE_NAME