Question

我在PHP中有一个数组： -

$arr = ["BX_NAME0","BX_NAME1","BX_NAME2","BX_categoryName0","BX_categoryName1","BX_categoryName2","BHA_categories0","BHA_categories1","BHA_categories2"]

这里我想在json中将基于相同结束整数的元素组合在一起，如

$post_data = array(
      '0' => array(
        'BX_NAME0' => $item_type,
        'BX_categoryName0' => $string_key,
        'BHA_categories0' => $string_value
      ),
      '1' => array(
        'BX_NAME1' => $item_type,
        'BX_categoryName1' => $string_key,
        'BHA_categories1' => $string_value
      ),
);

我用过： - filter_var($key , FILTER_SANITIZE_NUMBER_INT);

获取数组元素的整数部分，但不知道如何进一步对它们进行分组。

Answer 1

您可以使用preg_match（）执行以下操作： -

$new_array = array();

foreach ($arr as $ar){
   preg_match_all('!\d+!', $ar, $matches); //get the number from string
   $new_array[$matches[0][0]][$ar] = '';

}
echo "<pre/>";print_r($new_array);

输出： - https://eval.in/715548

Answer 2

它应该是这样的： -

$arr = array("BX_NAME0","BX_NAME1","BX_NAME2","BX_categoryName0","BX_categoryName1","BX_categoryName2","BHA_categories0","BHA_categories1","BHA_categories2");

$post_data = array();

foreach($arr as $value) {
    $key = filter_var($value , FILTER_SANITIZE_NUMBER_INT);
    if(isset($post_data[$key]) && !is_array($post_data[$key])) {
         $post_data[$key] = array();
    }
    $post_data[$key][] = $value;
}

print_r($post_data);

经过测试和工作但是，我建议您使用substr（）来获取数组项的最后一个字符，以获得性能和内容..

Answer 3

使用filter_var()方法

$arr = ["BX_NAME0","BX_NAME1","BX_NAME2","BX_categoryName0","BX_categoryName1","BX_categoryName2","BHA_categories0","BHA_categories1","BHA_categories2"];
    foreach($arr as $a){
        $int = filter_var($a, FILTER_SANITIZE_NUMBER_INT);
        $newarr[$int][$a] = '';
    }
    print_r($newarr);

输出： - https://eval.in/715581

将数组元素组合在一起

3 个答案: