如何将下面的sql查询转换为yii2代码

Question

SELECT student_subjects.student_id，student_subjects.subject_id，student_subjects.amount FROM student_subjects NOT NOT EXISTS（来自payment_history的subject subject_id，其中student_subjects.subject_id = payment_history.subject_id）

Answer 1

试试这个

$sql="SELECT student_subjects.student_id,student_subjects.subject_id,student_subjects.amount FROM student_subjects where NOT EXISTS(SELECT subject_id from payment_history where student_subjects.subject_id=payment_history.subject_id)"
Yii::app()->db->createCommand($sql)->queryAll();