Question

有人可以告诉我为什么以下代码不会在Chisel中详细说明？看来我无法分配给UInt中的各个位。这是设计的吗？

我确实看到了杰克对类似问题的回答，但是以下类型的逻辑跨越了一些链的常见且很容易在SV等参数化。我可以看到创建一个Bool的Vector以及个别位，但仍然是如何回到UInt的问题...

  def ffo(pwidth:Int, in:UInt) : UInt = {
    val rval = Wire(UInt(width=pwidth))
    rval(0) := in(0)
    for(w <- 1 until pwidth) {
      rval(w) := in(w) & !( in(w-1,0).orR() )
    }
    rval
  }

结果：

firrtl.passes.CheckGenders$WrongGender:  @[Misc.scala 21:13:@5808.4]: [module IuIrRename]  Expression T_1824 is used as a FEMALE but can only be used as a MALE.
firrtl.passes.CheckGenders$WrongGender:  @[Misc.scala 23:15:@5815.4]: [module IuIrRename]  Expression T_1826 is used as a FEMALE but can only be used as a MALE.
firrtl.passes.CheckGenders$WrongGender:  @[Misc.scala 23:15:@5822.4]: [module IuIrRename]  Expression T_1834 is used as a FEMALE but can only be used as a MALE.
firrtl.passes.CheckGenders$WrongGender:  @[Misc.scala 23:15:@5829.4]: [module IuIrRename]  Expression T_1842 is used as a FEMALE but can only be used as a MALE.
firrtl.passes.CheckGenders$WrongGender:  @[Misc.scala 21:13:@5834.4]: [module IuIrRename]  Expression T_1851 is used as a FEMALE but can only be used as a MALE.

Answer 1

在继续实验之后（以及查看生成的Verilog之后），以下代码与我正在寻找的代码相同：

  def ffo(pwidth:Int, in:UInt) : UInt = {
    val ary = Wire(Vec(pwidth, Bool()))
    ary(0) := in(0)
    for(w <- 1 until pwidth) {
      ary(w) :=   in(w) && !( in(w-1,0).orR() )
    }
    val rval = Reverse(Cat(ary))
    rval
  }

分配给UInt的各个位的凿子

1 个答案: