如何解析URL以获取它在groovy中的参数？

Question

我是groovy脚本的新手，并且正在寻找解析URL并打印它的参数。

此网址为：https://www.google.com/?aaa=111&bbb=222&ccc=33&dd=1484088989_b23f248ac6e5d9a9b47475526bb92ee1

如何从网址

获取 dd 参数？

感谢您的帮助！

Answer 1

您需要添加一个groovy脚本。

def groovyUtils = new com.eviware.soapui.support.GroovyUtils( context );
def testCase = context.testCase;
def testStep = testCase.getTestStepByName("NAME_TESTStepRequest");  
def endpoint =testStep.getPropertyValue('Endpoint');
log.info endpoint;
def url = new URL(endpoint)
//def url = new URL("https://www.google.com/?aaa=111&bbb=222&ccc=33&dd=1484088989_b23f248ac6e5d9a9b47475526bb92ee1")

// get all query params as list
def queryParams = url.query?.split('&') // safe operator for urls without query params
// transform the params list to a Map spliting 
// each query param
def mapParams = queryParams.collectEntries { param -> param.split('=').collect { URLDecoder.decode(it) }}
// assert the expected values
log.info mapParams['aaa']
//assert mapParams['aaa'] == '111'
log.info mapParams['bbb']
//assert mapParams['bbb']== 'abc'
log.info mapParams['dd']
//assert mapParams['dd']=='023423'

请你查看这篇文章。Get query params from request url soapui using groovy