Question

假设我将此作为URL

https://localhost/?username=john_small，我想获取用户名并显示例如：

在PHP中，我可以做这样的事情

$username = $_GET['username']

然后显示我所做的事情

<?php echo $username;?>

现在在Java中，我也可以做类似的事情

String username = request.getParameters("username");

我应该显示它吗，我做类似

<% "Hello" + <%=username%>; %>

例如，现在我想在groovy中做同样的事情，我可以像在Java中一样使用相同的东西吗？我在这里迷失了想法

Answer 1

我认为我回答这个问题的时间太晚了，因为我才有机会使用SOAP UI：

以下作品：

import os, re, shutil

import spotipy
import spotipy.util as util
import time

# Parameters
username      = 'REDACTED'
client_id     = 'REDACTED'
client_secret = 'REDACTED'
redirect_uri  = 'http://localhost/'
scope         = 'user-library-read'
playlist      = '17gneMykp6L6O5R70wm0gE'


def show_tracks(tracks):
    for i, item in enumerate(tracks['items']):
        track = item['track']
        myName = re.sub('[^A-Za-z0-9\ ]+', '', track['name'])
        dirName = "/Users/pschorn/Songs/" + myName + ".app"
        if os.path.exists(dirName):
            continue
            #shutil.rmtree(dirName)
        os.mkdir(dirName)
        os.mkdir(dirName + "/Contents")
        with open(dirName + "/Contents/PkgInfo", "w+") as f:
            f.write("APPL????")
        os.mkdir(dirName + "/Contents/MacOS")
        with open(dirName + "/Contents/MacOS/" + myName, "w+") as f:
            f.write("#!/bin/bash\n")
            f.write("osascript -e \'tell application \"Spotify\" to play track \"{}\"\'".format(track['uri']))
        os.lchmod(dirName + "/Contents/MacOS/" + myName, 0o777)

        myName = re.sub('\ ', '\\ ', myName)
        # I've installed a third-party command-line utility that
        # allows me to set the icon for applications.
        # If there's a way to do this from python, let me know.
        os.system(
            '/usr/local/bin/fileicon set /Users/pschorn/Songs/' + myName + '.app /Users/pschorn/Code/PyCharmSupport/Icon.icns')





token = util.prompt_for_user_token(username, scope, client_id, client_secret, redirect_uri)

if token:
    sp = spotipy.Spotify(auth=token)
    results = sp.user_playlist(username, playlist, fields="tracks,next")
    tracks = results['tracks', offset=100]
    show_tracks(tracks)

else:
    print("Can't get token for", username)

在Groovy中获取URL参数

1 个答案: