Question

我正在尝试将某些SSL发现扫描的结果输出为用于报告目的的表格，并且我在以我想要的方式解析数据时遇到了一些问题。

我希望输出看起来像这样：

IP Address    Common Name             Valid To
------------  ----------------------  ----------
10.0.255.250   ex.example.com  2017/02/09
10.0.255.251   localhost      2009/07/04
10.0.255.252    ex.example2.com     2016/05/24

相反，它看起来像这样。

IP Address    Common Name             Valid To
------------  ----------------------  ----------
10.0.255.250   ex.example.com  2017/02/09
IP Address    Common Name    Valid To
------------  -------------  ----------
10.0.255.251   localhost      2009/07/04
None
IP Address    Common Name    Valid To
------------  -------------  ----------
10.0.255.252    ex.example2.com     2016/05/2

我一直在尝试使用while循环来解决这个问题并且没有运气。它似乎不是一个＆＃34;而＃34;循环和更多的＆＃34;为每个＆＃34;循环。

def tabulateText():
    loop = True
    while loop == True:
        with open("testinput.txt", "r") as text_file:
            for line in text_file:
                if "end" in line:
                    loop = False
                elif "IP Address =" in line:
                    start = line.find('IP Address = ')
                    endline = line.find('\n', start)
                    ip = line[start+13:endline]
                    cert = SSLmon(ip)
                    Col1 = ip
                    FCS2 = cert.find('commonName')
                    FCE2 = cert.find('/', FCS2)
                    FCS2b = cert.find('commonName')
                    FCE2b = cert.find('\n', FCS2b)
                    Colopt2 = cert[FCS2+11:FCE2]
                    Colopt2b = cert[FCS2b+11:FCE2b]
                    Col2 = cert[FCS2+11:FCE2] if len(Colopt2) < len(Colopt2b) else cert[FCS2b+11:FCE2b]
                    FCS3 = cert.find('Not valid after:')
                    FCE3 = cert.find('T', FCS3)
                    Col3 = cert[FCS3+18:FCE3].replace('-', '/')
                    column = Col1[n], Col2[n], Col3[n]
                    print(tabulate([column], headers=['IP Address', 'Common Name', 'Valid To']))
                else:
                    pass

print(tabulateText())
print(tabulateText())
print(tabulateText())

Answer 1

每次读取“IP地址”行后都会执行print（tabulate（[column]，headers ..）命令，这就是为什么你会看到标题和只有一行数据的原因。

您可以做的是将每行结果（您称之为“列”）附加到数组中。这将创建一个包含所有结果的表格。在阅读完文件的所有行后，执行print（tabulate（））命令。。

首先，在读取文本文件之前创建一个空数组 - 我将其称为表：

table = [] 
  with open("testinput.txt", "r") as text_file:

将列数组追加到表数组（table.append [column]）并删除当前具有的print（tabulate（））命令。

column = Col1[n], Col2[n], Col3[n]
table.append[column]

在读完文件并引用新变量“table”之后，在最后移动print（tabulate（））命令。

print (tabulate(table), headers=['...'])

您不需要循环 - “for line”命令循环遍历文本文件。此外，完成后关闭文件（text_file.closed）

该功能将如下所示：

table = []
with open("testinput.txt", "r") as text_file:
    for line in text_file:
        if "IP Address =" in line:
            start = line.find('IP Address = ')
            endline = line.find('\n', start)
            ip = line[start+13:endline]
            cert = SSLmon(ip)
            Col1 = ip
            FCS2 = cert.find('commonName')
            FCE2 = cert.find('/', FCS2)
            FCS2b = cert.find('commonName')
            FCE2b = cert.find('\n', FCS2b)
            Colopt2 = cert[FCS2+11:FCE2]
            Colopt2b = cert[FCS2b+11:FCE2b]
            Col2 = cert[FCS2+11:FCE2] if len(Colopt2) < len(Colopt2b) else cert[FCS2b+11:FCE2b]
            FCS3 = cert.find('Not valid after:')
            FCE3 = cert.find('T', FCS3)
            Col3 = cert[FCS3+18:FCE3].replace('-', '/')
            column = Col1[n], Col2[n], Col3[n]
            table.append[column]
    text_file.closed
    print(tabulate([table], headers=['IP Address', 'Common Name', 'Valid To']))

表数组本身看起来像这样你是做print（table）命令：

[['10.0.255.250'，'ex.example.com'，'2017/02/09']，['10.0.255.251'，'localhost'，'2009/07/04']，[' 10.0.255.252' ， 'ex.example2.com'， '2016年5月24日']]

Answer 2

我最终采用了不同的方法来获取我想要的数据。我终于打印出每个列，并使用由.ljust()控制的填充。

with open("testinput.txt", "r") as text_file:
    for line in text_file:
        if "IP Address =" in line:
            start = line.find('IP Address = ')
            endline = line.find('\n', start)
            ip = line[start+13:endline]
            cert = SSLmon(ip)
            Col1 = ip
            FCS2 = cert.find('commonName')
            FCE2 = cert.find('/', FCS2)
            FCS2b = cert.find('commonName')
            FCE2b = cert.find('\n', FCS2b)
            Colopt2 = cert[FCS2+11:FCE2]
            Colopt2b = cert[FCS2b+11:FCE2b]
            Col2 = cert[FCS2+11:FCE2] if len(Colopt2) < len(Colopt2b) else cert[FCS2b+11:FCE2b]
            FCS3 = cert.find('Not valid after:')
            FCE3 = cert.find('T', FCS3)
            Col3 = cert[FCS3+18:FCE3].replace('-', '/')
            with open(filename1, 'a') as f:
                line = '%s %s %s %s' % (Col1.ljust(20), Col2.ljust(35), Col3.ljust(15), '\n')
                f.write(line)

存储每个循环，并在循环完成时输出到表

2 个答案: