Question

我正在使用slim-framework v2和php来获取json输出。使用此代码，我收到了关于该主题的错误。 mysql表的格式错误，现在无法更改，所以我以这种方式制作这些函数，因为我不是很有经验。解决这个问题的最佳方法是什么？如果可以使用sql命令完成更好，那么我可以从主循环中删除这些函数吗？循环中的函数是不是很糟糕？ ps：如果主题看起来不对，请告诉我。

test（）是客户ID的主要循环

function test($server, $user, $pass, $db) {
  $result = array();
  $sql = "SELECT cid from tasks where total!=0";
  $db = newDB($server, $user, $pass, $db);
  $stmt = $db->prepare($sql);
  $stmt->execute();
  foreach ($stmt as $v) {
    $result[] = ['cid'=> $v['cid'], 'test'=> toGet($server, $user, $pass, $db, $v['cid']), 'test2'=> toGet2($server, $user, $pass, $db, $v['cid'])];
  }
  echo json_encode($result, JSON_FORCE_OBJECT);
}

和其他功能

function toGet($server, $user, $pass, $db, $id) {
  $sql = "SELECT sum(`poso`) as posoe from `economics` where `custid`=:id and flag=0";
  $db = newDB($server, $user, $pass, $db);
  $stmt = $db->prepare($sql);
  $stmt->bindParam("id", $id);
  $stmt->execute();
  $row = $stmt->fetch(PDO::FETCH_NUM);
  return $row[0];
}

function toGet2($server, $user, $pass, $db, $id) {
  $sql = "SELECT sum(`poso`) as posoe from `economics` where `custid`=:id and flag=1";
  $db = newDB($server, $user, $pass, $db);
  $stmt = $db->prepare($sql);
  $stmt->bindParam("id", $id);
  $stmt->execute();
  $row = $stmt->fetch(PDO::FETCH_NUM);
  return $row[0];
}

非常感谢！

更新打开debug $ app-＆gt; config（'debug'，true），最终得到了错误键入：ErrorException 代码：4096 消息：类PDO的对象无法转换为字符串文件：/var/www/api/newdb.php 行：6

function newDB($host, $user, $pass, $db) {
    $dbhost= $host;
    $dbuser= $user;
    $dbpass= $pass;
    $dbname= $db;
    $dbConnection = new PDO("mysql:host=$dbhost;dbname=$dbname", $dbuser, $dbpass);
    $dbConnection->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
    $dbConnection->query('set names utf8');
    return $dbConnection;
}

UPDATE2：Slim conf

include 'newdb.php';
require 'Slim/Slim.php';
\Slim\Slim::registerAutoloader();
$app = new \Slim\Slim();
$app->config('debug', true);
$app->response->setStatus(200);
$app->contentType('application/json; charset=utf-8');
$app->get('/test/:server/:user/:pass/:db', 'test');
$app->get('/', function() use($app) {
    $app->response->setStatus(200);
    echo "Welcome!";
});
$app->run();

Answer 1

问题由Freenode上的一个人通过单个MYSQL查询解决。

- Reconnecting on db for each query was bad.
- toGet() toGet2() removed

我可以使用单个查询

获取数据

SELECT t1.custid as cid, sum(if(t2.flag=0,t2.poso,0)) as posoX,
sum(if(t2.flag=1,t2.poso,0)) as posoY from tasks t1 
left join economics t2 on t2.custid=t1.custid and t2.flag in (0,1) group by t1.custid;

错误：类PDO的对象无法转换为字符串

1 个答案: