Question

我需要使用XSLT（遗憾的是版本1）我试图通过比较子节点中的两个属性来过滤掉某些节点。

这是XML：

<?xml version="1.0" encoding="UTF-8"?>
<SOAP-ENV:Envelope xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/">
  <SOAP-ENV:Header xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/">
  </SOAP-ENV:Header>
  <SOAP-ENV:Body xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/">
    <QueriesResponse xmlns="http://schemas.Movies.com/Movies">
      <Films xmlns="http://schemas.Movies.com/Movies">
        <Film>
          <FilmPostings>
            <FilmPosting>
              <FilmPostingDates>
                <FilmPostDate>2017-01-04T19:44:25.9530000-05:00</FilmPostDate>
                <FilmActiveDate>2017-01-04T19:44:25.9530000-05:00</FilmActiveDate>
              </FilmPostingDates>
            </FilmPosting>
          </FilmPostings>
        </Film>
        <Film>
          <FilmPostings>
            <FilmPosting>
              <FilmPostingDates>
                <FilmPostDate>2017-01-04T19:50:06.3830000-05:00</FilmPostDate>
                <FilmActiveDate>2017-01-04T19:50:06.3100000-05:00</FilmActiveDate>
              </FilmPostingDates>
            </FilmPosting>
          </FilmPostings>
        </Film>
        <Film>
          <FilmPostings>
            <FilmPosting>
              <FilmPostingDates>
                <FilmPostDate>2016-12-05T18:03:14.9830000-05:00</FilmPostDate>
                <FilmActiveDate>2017-01-02T00:16:52.7570000-05:00</FilmActiveDate>
              </FilmPostingDates>
            </FilmPosting>
          </FilmPostings>
        </Film>
      </Films>
    </QueriesResponse>
  </SOAP-ENV:Body>
</SOAP-ENV:Envelope>

这是我的转变：

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
                xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
                xmlns="http://schemas.Movies.com/Movies"
                xmlns:m="http://schemas.Movies.com/Movies"
                exclude-result-prefixes="m"
                >
  <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes" />

  <!-- standard identity template -->
  <xsl:template match="node()|@*">
    <xsl:copy>
      <xsl:apply-templates select="node()|@*"/>
    </xsl:copy>
  </xsl:template>

  <!-- This is mean to compare PostDate and ActiveDate, matching if different. It doesn't match any nodes in XML (but should match the final one). -->
  <xsl:template match="m:Film[m:FilmPostings/m:FilmPosting/m:FilmPostingDates/m:FilmPostDate[1] [.!= m:FilmPostings/m:FilmPosting/m:FilmPostingDates/m:FilmActiveDate[1]]]">
  </xsl:template>

  <!-- This code does match the hard coded value (the second node).  -->  
  <!--<xsl:template match="m:Film[m:FilmPostings/m:FilmPosting/m:FilmPostingDates/m:FilmPostDate[1] [.!= '2017-01-04T19:50:06.3830000-05:00']]">    
  </xsl:template>-->

</xsl:stylesheet>

所以，你会在注释掉的位中看到我可以与硬编码值匹配，所以我显然在正确的区域 - 我知道代码将排除整个电影节点，如果它找到匹配。但它正在比较两个不起作用的节点值。

我在比较的右侧尝试了各种变体，但它似乎无法获取ActiveDate的值。

Answer 1

要移除Film和FilmPostDate FilmActiveDate元素，您可以在匹配属性中实际嵌套条件

<xsl:template 
     match="m:Film[m:FilmPostings/m:FilmPosting/m:FilmPostingDates[m:FilmPostDate = m:FilmActiveDate]]" />

这假定每FilmPostDate只有一组FilmActiveDate和Film个元素。如果有多个集合，您可以尝试删除所有出现次数相同的Film元素（或者更确切地说，不存在不同的出现次数）。

<xsl:template 
     match="m:Film[not(m:FilmPostings/m:FilmPosting/m:FilmPostingDates[m:FilmPostDate != m:FilmActiveDate])]" />

XSLT筛选器比较同一子节点中的两个值

1 个答案: