我打算建造一个天线跟踪器。我需要从具有高度的GPS点A和具有高度的GPS点B获得方位和倾斜。
这是示例点:
latA = 39.099912
lonA = -94.581213
altA = 273.543
latB = 38.627089
lonB = -90.200203
altB = 1380.245
我已经有了水平轴承的公式,它给了我97.89138167122422
这是代码:
function toRadian(num) {
return num * (Math.PI / 180);
}
function toDegree(num) {
return num * (180 / Math.PI);
}
function getHorizontalBearing(fromLat, fromLon, toLat, toLon) {
fromLat = toRadian(fromLat);
fromLon = toRadian(fromLon);
toLat = toRadian(toLat);
toLon = toRadian(toLon);
let dLon = toLon - fromLon;
let x = Math.tan(toLat / 2 + Math.PI / 4);
let y = Math.tan(fromLat / 2 + Math.PI / 4);
let dPhi = Math.log(x / y);
if (Math.abs(dLon) > Math.PI) {
if (dLon > 0.0) {
dLon = -(2 * Math.PI - dLon);
} else {
dLon = (2 * Math.PI + dLon);
}
}
return (toDegree(Math.atan2(dLon, dPhi)) + 360) % 360;
}
let n = getHorizontalBearing(39.099912, -94.581213, 38.627089, -90.200203);
console.info(n);
但我不知道如何找到倾斜角度。有人可以帮帮我吗?
答案 0 :(得分:2)
我想我在搜索后得到了答案。
这是完整的代码,如果您认为这是错误的,请随时纠正我。
function toRadian(num) {
return num * (Math.PI / 180);
}
function toDegree(num) {
return num * (180 / Math.PI);
}
// North is 0 degree, South is 180 degree
function getHorizontalBearing(fromLat, fromLon, toLat, toLon, currentBearing) {
fromLat = toRadian(fromLat);
fromLon = toRadian(fromLon);
toLat = toRadian(toLat);
toLon = toRadian(toLon);
let dLon = toLon - fromLon;
let x = Math.tan(toLat / 2 + Math.PI / 4);
let y = Math.tan(fromLat / 2 + Math.PI / 4);
let dPhi = Math.log(x / y);
if (Math.abs(dLon) > Math.PI) {
if (dLon > 0.0) {
dLon = -(2 * Math.PI - dLon);
} else {
dLon = (2 * Math.PI + dLon);
}
}
let targetBearing = (toDegree(Math.atan2(dLon, dPhi)) + 360) % 360;
return targetBearing - currentBearing;
}
// Horizon is 0 degree, Up is 90 degree
function getVerticalBearing(fromLat, fromLon, fromAlt, toLat, toLon, toAlt, currentElevation) {
fromLat = toRadian(fromLat);
fromLon = toRadian(fromLon);
toLat = toRadian(toLat);
toLon = toRadian(toLon);
let fromECEF = getECEF(fromLat, fromLon, fromAlt);
let toECEF = getECEF(toLat, toLon, toAlt);
let deltaECEF = getDeltaECEF(fromECEF, toECEF);
let d = (fromECEF[0] * deltaECEF[0] + fromECEF[1] * deltaECEF[1] + fromECEF[2] * deltaECEF[2]);
let a = ((fromECEF[0] * fromECEF[0]) + (fromECEF[1] * fromECEF[1]) + (fromECEF[2] * fromECEF[2]));
let b = ((deltaECEF[0] * deltaECEF[0]) + (deltaECEF[2] * deltaECEF[2]) + (deltaECEF[2] * deltaECEF[2]));
let elevation = toDegree(Math.acos(d / Math.sqrt(a * b)));
elevation = 90 - elevation;
return elevation - currentElevation;
}
function getDeltaECEF(from, to) {
let X = to[0] - from[0];
let Y = to[1] - from[1];
let Z = to[2] - from[2];
return [X, Y, Z];
}
function getECEF(lat, lon, alt) {
let radius = 6378137;
let flatteningDenom = 298.257223563;
let flattening = 0.003352811;
let polarRadius = 6356752.312106893;
let asqr = radius * radius;
let bsqr = polarRadius * polarRadius;
let e = Math.sqrt((asqr-bsqr)/asqr);
// let eprime = Math.sqrt((asqr-bsqr)/bsqr);
let N = getN(radius, e, lat);
let ratio = (bsqr / asqr);
let X = (N + alt) * Math.cos(lat) * Math.cos(lon);
let Y = (N + alt) * Math.cos(lat) * Math.sin(lon);
let Z = (ratio * N + alt) * Math.sin(lat);
return [X, Y, Z];
}
function getN(a, e, latitude) {
let sinlatitude = Math.sin(latitude);
let denom = Math.sqrt(1 - e * e * sinlatitude * sinlatitude);
return a / denom;
}
let n = getHorizontalBearing(39.099912, -94.581213, 39.099912, -94.588032, 0.00);
console.info("Horizontal bearing:\t", n);
let m = getVerticalBearing(39.099912, -94.581213, 273.543, 39.099912, -94.588032, 873.543, 0.0);
console.info("Vertical bearing:\t", m);
答案 1 :(得分:0)
Don Cross的javascript code产生了不错的结果。它考虑了地球的曲率以及地球是oblate的事实。
示例:
prices = {"banana": 4,"apple": 2,"orange": 1.5,"pear": 3} #prices dict
stock = {"banana": 6, "apple": 0, "orange": 32, "pear": 15} #stock dict
for food in prices: #iterate over the keys of prices dict
print food #print the key
print "price: %s" % prices[food] #print the value of prices dict at food key
print "stock: %s" % stock[food] #print the value of stock dict at food key