我想要了解位屏蔽,我对某些结果有疑问。这是一些示例代码。
FILE * pFile;
long lSize;
char * buffer;
size_t result;
pFile = fopen ( "testFile.jpg" , "rb" );
if (pFile==NULL) {fputs ("File error",stderr); exit (1);}
// obtain file size:
fseek (pFile , 0 , SEEK_END);
lSize = ftell (pFile);
rewind (pFile);
// allocate memory to contain the whole file:
buffer = (char*) malloc (sizeof(char)*lSize);
if (buffer == NULL) {fputs ("Memory error",stderr); exit (2);}
// copy the file into the buffer:
result = fread (buffer,1,lSize,pFile);
if (result != lSize) {fputs ("Reading error",stderr); exit (3);}
/* the whole file is now loaded in the memory buffer. */
for (unsigned long long e = 0; e < lSize; e++){
unsigned short val1 = buffer[e] & 0x3;
cout << val1 << endl;
if (1 == val1){
}
if (1 == buffer[e] & 0x3){
//what does buffer[e] & 0x3 equal when I don't set it equal to an unsigned short.
}
}
因此,如果我输出val1
的值,我总是得到一个0到3之间的值。但是当我进行比较而没有为buffer[e] & 0x3
分配类型时,我总是得到同样的结果。我试图输出buffer[e] & 0x3
来查看它等于什么,但是我收到错误。所以我的问题是buffer[e] & 0x3
在第二个if语句中使用时的可能值是什么。感谢。
答案 0 :(得分:2)
因为运算符优先级
7 == != For relational = and ≠ respectively
8 & Bitwise AND
因此==
优先于&
(1 == buffer[e] & 0x3)
与
不同(1 == (buffer[e] & 0x3))
但是
((1 == buffer[e]) & 0x3)
(相当于(1 == buffer[e])
,因为屏蔽0或1与3无效)
你想要的是(1 == (buffer[e] & 0x3))
答案 1 :(得分:2)
似乎是运算符优先级的问题: http://en.cppreference.com/w/cpp/language/operator_precedence
1 == buffer[e] & 0x3
相当于
(1 == buffer[e]) & 0x3