Codeigniter为您提供了一个了解它以及如何使用它的教程。本教程教您在数据库的表中创建元素,但不教您如何更新此元素。我正在尝试使用codeigniter库进行更新查询,但de update视图中的表单不会提交。
AT NEWS_MODEL:
public function update_news($slug)
{
$this->load->helper('url');
$data = array(
'title' => $this->input->post('title'),
'slug' => $slug,
'text' => $this->input->post('text')
);
$this->db->where('slug', $slug);
$this->db->update('news', $data);
}
新闻控制器:
public function update($slug)
{
$this->load->helper('form');
$this->load->library('form_validation');
$data['title'] = 'Update a news item';
$this->form_validation->set_rules('title', 'Title', 'required');
$this->form_validation->set_rules('text', 'Text', 'required');
if ($this->form_validation->run() === FALSE)
{
// The form was NOT posted
// So we load the view
$data['news_item'] = $this->news_model->get_news($slug);
$this->load->view('templates/header', $data);
$this->load->view('news/update', $data);
$this->load->view('templates/footer');
}
else
{
// The form was submitted
$data = array(
'title' => $this->input->post('title'), //-->post variable
'slug' => $this->input->post('slug'),
'text' => $this->input->post('text')
);
$this->news_model->update_news($slug, $data);
$this->load->view('news/success');
}
}
AT UPDATE VIEW:
<h2><?php echo $title; ?></h2>
<?php echo validation_errors(); ?>
<?php echo form_open('news/update') ;?>
<label for="title">Title</label>
<input type="input" name="title" /><br />
<label for="text">Text</label>
<textarea name="text"></textarea><br />
<input type="submit" name="submit" value="Update news item" />
</form>
我用“console.log()”测试了代码,问题似乎是更新视图的表单没有提交,但我无法理解为什么,因为表单类似于创建表单,它确实有效:
<h2><?php echo $title; ?></h2>
<?php echo validation_errors(); ?>
<?php echo form_open('news/create'); ?>
<label for="title">Title</label>
<input type="input" name="title" /><br />
<label for="text">Text</label>
<textarea name="text"></textarea><br />
<input type="submit" name="submit" value="Create news item" />
</form>
答案 0 :(得分:0)
你的问题是:
您在此行中使用===
代替==
:
if ($this->form_validation->run() === FALSE)