Codeigniter更新表单不提交

时间:2017-01-06 18:42:16

标签: javascript php mysql forms codeigniter

Codeigniter为您提供了一个了解它以及如何使用它的教程。本教程教您在数据库的表中创建元素,但不教您如何更新此元素。我正在尝试使用codeigniter库进行更新查询,但de update视图中的表单不会提交。

AT NEWS_MODEL:

public function update_news($slug)
			{

			$this->load->helper('url');

			$data = array(
			               'title' => $this->input->post('title'),
			               'slug' => $slug,
			               'text' => $this->input->post('text')
			            );

			$this->db->where('slug', $slug);
			$this->db->update('news', $data); 

			}

新闻控制器:

public function update($slug)
        {

            $this->load->helper('form');
            $this->load->library('form_validation');

            $data['title'] = 'Update a news item';

            $this->form_validation->set_rules('title', 'Title', 'required');
            $this->form_validation->set_rules('text', 'Text', 'required');


            if ($this->form_validation->run() === FALSE)
            {
              // The form was NOT posted
              // So we load the view
              $data['news_item'] = $this->news_model->get_news($slug);
              $this->load->view('templates/header', $data);
              $this->load->view('news/update', $data);
              $this->load->view('templates/footer');

            }
            else
            {
              // The form was submitted
              $data = array(
           'title' => $this->input->post('title'), //-->post variable
           'slug'  => $this->input->post('slug'),
           'text' => $this->input->post('text')
                );

              $this->news_model->update_news($slug, $data);
              $this->load->view('news/success');
            }
          }

AT UPDATE VIEW:

<h2><?php echo $title; ?></h2>

<?php echo validation_errors(); ?>

<?php  echo form_open('news/update') ;?>

<label for="title">Title</label>
<input type="input" name="title" /><br />

<label for="text">Text</label>
<textarea name="text"></textarea><br />

<input type="submit" name="submit" value="Update news item" />

</form>

我用“console.log()”测试了代码,问题似乎是更新视图的表单没有提交,但我无法理解为什么,因为表单类似于创建表单,它确实有效:

<h2><?php echo $title; ?></h2>

<?php echo validation_errors(); ?>

<?php echo form_open('news/create'); ?>

    <label for="title">Title</label>
    <input type="input" name="title" /><br />

    <label for="text">Text</label>
    <textarea name="text"></textarea><br />

    <input type="submit" name="submit" value="Create news item" />

</form>

1 个答案:

答案 0 :(得分:0)

你的问题是: 您在此行中使用===代替==

 if ($this->form_validation->run() === FALSE)